Category Archives: Java Programs

Java Programs

ATM program In Java

In this tutorial, we will learn to create a Java Program of ATM program In Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

Here we Build a Java Program, to show how ATM Transaction takes place,here a User has to choose options which are displayed on the Screen.

Following operations available in the ATM.

Withdraw
Deposit
Check Balance
Exit.

Create a ATM program In Java programming.

In this program , we will create a ATM Mechanism In Java, we can create an ATM program for representing ATM transaction we will use options related to withdraw money, deposit, check balance, and exit from transaction.Let look at the code of this program.

//java program to create a ATM Program using swicth case..   
import java.util.Scanner;  
public class ATM  
{  
    //declare variables and take a value from user at run time
    public static void main(String args[] )  
    {  
        int bal = 100000, with_draw, deposit;  
        Scanner sc = new Scanner(System.in);  
          
        while(true)  
        {  
            System.out.println("ATM");  
            System.out.println("Choose 1 for Withdraw");  
            System.out.println("Choose 2 for Deposit");  
            System.out.println("Choose 3 for Check Balance");  
            System.out.println("Choose 4 for EXIT");  
            System.out.print("Choose any operation you want to perform:");  
              
            //take a choice from user 
            int ch = sc.nextInt();  
            switch(ch)  
            {  
                case 1:  
        System.out.print("Enter money to be withdrawn from a/c:");  
                      
        //get the withdrawl amount from user..
        with_draw = sc.nextInt();  
                      
        //check conditon for balance is greater than or equal to the withdrawal amount . 
        if(bal >= with_draw)  
        {  
            //Deduct the withdrawl amount from  total balance  
            bal = bal - with_draw;  
            System.out.println("Please collect your money");  
        }  
        else  
        {  
            //show erroe if amount is greater than balanace 
            System.out.println("Insufficient Balance");  
        }  
        System.out.println("");  
        break;  
   
                case 2:  
                      
        System.out.print("Enter money to be deposited:");  
                      
        //get deposite amount from te user  
        deposit = sc.nextInt();  
                      
        //add  amount to the total balanace  .
        bal = bal + deposit;  
        System.out.println("Your Money has been successfully depsited");  
        System.out.println("");  
        break;  
   
                case 3:  
        //displaying balance of the user..  
        System.out.println("Balance : "+bal);  
        System.out.println("");  
        break;  
   
                case 4:  
        //exit from the menu  
        System.exit(0);  
            }  
        }  
    }  
}

//java program to create a ATM Program using swicth case..

import java.util.Scanner;

public class ATM

{

//declare variables and take a value from user at run time

public static void main(String args[] )

{

int bal = 100000, with_draw, deposit;

Scanner sc = new Scanner(System.in);

while(true)

{

System.out.println("ATM");

System.out.println("Choose 1 for Withdraw");

System.out.println("Choose 2 for Deposit");

System.out.println("Choose 3 for Check Balance");

System.out.println("Choose 4 for EXIT");

System.out.print("Choose any operation you want to perform:");

//take a choice from user

int ch = sc.nextInt();

switch(ch)

{

case 1:

System.out.print("Enter money to be withdrawn from a/c:");

//get the withdrawl amount from user..

with_draw = sc.nextInt();

//check conditon for balance is greater than or equal to the withdrawal amount .

if(bal >= with_draw)

{

//Deduct the withdrawl amount from total balance

bal = bal - with_draw;

System.out.println("Please collect your money");

}

else

{

//show erroe if amount is greater than balanace

System.out.println("Insufficient Balance");

}

System.out.println("");

break;

case 2:

System.out.print("Enter money to be deposited:");

//get deposite amount from te user

deposit = sc.nextInt();

//add amount to the total balanace .

bal = bal + deposit;

System.out.println("Your Money has been successfully depsited");

System.out.println("");

break;

case 3:

//displaying balance of the user..

System.out.println("Balance : "+bal);

System.out.println("");

break;

case 4:

//exit from the menu

System.exit(0);

}

Output

In the above program, we have first declared and initialized a set variables required in the program.

bal = it will hold balance amount.
with_draw= it wil hold value of prime number.
deposit= it will hold deposit.

After declaring variables we take a nth value of from user.

Now user will choose any one available options and input the number with.here we use different cases using switch case that have been provided to user like withdraw, deposit and check balance.As shown in the image suppose user choose the option 3 then the output of program is show balance.

and again ask user to input different value for perform different operations.

following are the switch case condition according to option for different case are as follow

case 1: for withdraw.

case 2: for Deposit

Case 3: for Check Balance.

Case 4 : for exit

Approach to Check Balance

show the balance amount in the screen.

Program to check Spy Number in Java

In this tutorial, we will learn to create a Java Program to check Spy Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Spy Number in Java

A Number is called a Spy number if sum(1+3+2=6) and product(1*3*6=6) of its digits are equal.

Example:-> Number “22”=> sum(2+2=4) and Product (2*2=4) then “22” is a Spy Number.

Program to check Spy Number in Java

In this program , we will find given number is a Spy number or not .First of all user will be prompted to enter Number and afterword we will find the given number is a Spy Number or not. Lets have look at the code.

// Java Program to Check If a Number is Spy number or not
import java.io.*;
import java.util.Scanner;  

class GFG {
	public static void main(String[] args)
	{
	    // Taking value form user..
         Scanner s= new Scanner(System.in);
         System.out.println("Enter any number:"); 
         int number= s.nextInt();
         

		int copy, multi = 1, sum = 0, temp;
        copy=number;
		// calculate sum and product of the number here.
		while (copy > 0) {
			temp = copy % 10;
			sum = sum + temp;
			multi = multi * temp;
			copy = copy / 10;
		}

		// compare the sum and product.
		if (sum == multi)
			System.out.println(
				"Given number is spy number "+ number);
		else
			System.out.println(
				"Given number is not spy number "+number);
	}
}

// Java Program to Check If a Number is Spy number or not

import java.io.*;

import java.util.Scanner;

class GFG {

public static void main(String[] args)

{

// Taking value form user..

Scanner s= new Scanner(System.in);

System.out.println("Enter any number:");

int number= s.nextInt();

int copy, multi = 1, sum = 0, temp;

copy=number;

// calculate sum and product of the number here.

while (copy > 0) {

temp = copy % 10;

sum = sum + temp;

multi = multi * temp;

copy = copy / 10;

}

// compare the sum and product.

if (sum == multi)

System.out.println(

"Given number is spy number "+ number);

else

System.out.println(

"Given number is not spy number "+number);

}

Output

Spy number

Not a Spy number.

In the above program, we have first declared and initialized a set variables required in the program.

number = it will hold entered number.
copy = it will hold entered number copy.
multi it will hold the result of multiplication of a number.
Sum=it will hold sum of digit.
Temp = it will old temp value of number.

Steps to Find Spy Number

take a value from user in (number).
take variables sum and product to store value of digit sum and product .
Initialize sum with 0 and product with 1.
Find the digit (copy%10) of a given number.
Add digit to the variable sum=sum+temp;
Multiply the digit with the multi= multi*temp;

Divide the number (number) by 10 to removes the last digit.
Repeat steps until the number become 0(Zero).
at last check values of sum and product are same, then number is a spy number,

else not a spy number.

Program to check Neon Number in Java

In this tutorial, we will learn to create a Java Program to check Neon Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Neon Number

A number is called a neon number if the sum of digits of the square of the number is equal to the number itself

For example:->

Square of “9 is 9*9 gives => 81.
sum of digit of square : 8+1=9 (which gives the number it self).
So “9″ is a Neon Number.

Program to check Neon Number in Java

In this program , we will find given number is a Neon number or not .First of all user will be prompted to enter Number and afterword we will find the given number is a Neon Number or not. Lets have look at the code.

import java.util.*;  
public class Neon_Num  
{  
public static void main(String args[])  
{  
int sum = 0;      
Scanner sc = new Scanner(System.in);  
System.out.print("Enter any number to check Neon number: ");  
//Declare variable and take value form user..
int number = sc.nextInt();  
//calculate square of a number  
int sqr = number* number;  
//executes until the condition false
while(sqr != 0)  
{  
//finding last digit of the square
int digit = sqr % 10;  
//adding digits to the variable sum 
sum = sum + digit;  
//removing the last digit 
sqr = sqr / 10;  
}  
//comparing number  with sum  
if(number == sum)  
System.out.println(number + " is a Neon Number.");  
else  
System.out.println(number + " is not a Neon Number.");  
}  
}

import java.util.*;

public class Neon_Num

{

public static void main(String args[])

{

int sum = 0;

Scanner sc = new Scanner(System.in);

System.out.print("Enter any number to check Neon number: ");

//Declare variable and take value form user..

int number = sc.nextInt();

//calculate square of a number

int sqr = number* number;

//executes until the condition false

while(sqr != 0)

{

//finding last digit of the square

int digit = sqr % 10;

//adding digits to the variable sum

sum = sum + digit;

//removing the last digit

sqr = sqr / 10;

}

//comparing number with sum

if(number == sum)

System.out.println(number + " is a Neon Number.");

else

System.out.println(number + " is not a Neon Number.");

}

Output

Neon Number

Not a Neon Number

In the above program, we have first declared and initialized a set variables required in the program.

number = it will hold entered number.
sqr = it will calculate Square of a number.
digit = for finding digit of a number
sum= sum of digit.

After that we take a number from user and find Neon number.

after that we will find square of digit and sum of square digit value as shown in image below.

then we check if sum of square digit equals to number then given number is Neon number.

Program to check Keith Number in Java

In this tutorial, we will learn to create a Java Program to check Keith Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Keith number in mathematics?

In mathematics a Keith numberKeith numbers are also called repfigit and it is a positive N-digit integer value where Number is greater than 9 such that if we create a series like – Fibonacci( Where each numbers/term in the following series is the sum of the n previous numbers/terms) and this series is formed by the sum of first n terms taken as the integervalue of the number N, then N itself occurs as a term in the series. i.e. 197 is a Keith number as it makes the series asfollows:

1, 9, 7,

1+9+7=17,

9+7+17=33,

7+17+33=57,

17+33+57=107,

33+57+107=197 ->(Keith).

Keith numbers are known as repfigit (repetitive fibonacci-like digit) numbers.

Here: –

N = number of digits of the term.

n = number of terms in the series.

Java Program to Find Keith Number

In this program we will find the number given by the user is a Keith number or not with the help of Java Program. We will first declare and initializethe required variables for the program. Next, we will prompt the user to input the value in integer format. Later we will check the given value is a Keith number or not.

import java.util.*;  
class KeithNumber
{  
Public static void main ()
{
	Scanner sc = new Scanner(System.in);
	System.out.println("Enter any number to check");
	int no = sc.nextInt(); // taking number value form user..
	int no1 = no;
	String s = Integer.toString(no);
	int d = s.length();
	int arr[] =new int[no];
	int i , sum;
	for(i=d-1;i>=0;i--)
		{
		arr[i] = no1%10;
		  no1=no1/10;
		} 
	i = d , sum =0;
	while (sum <no)
	{
		sum =0
		for(int j=1, j<=d,j++)
			{
			sum = sum+arr[i-j];
			}
		arr[i]=sum;
		i++;
		if (sum ==no)
			System.out.println("The given number is a keith number");
		else 
			System.out.println("The given number is not a Keith Number");
	}
}

import java.util.*;

class KeithNumber

{

Public static void main ()

{

Scanner sc = new Scanner(System.in);

System.out.println("Enter any number to check");

int no = sc.nextInt(); // taking number value form user..

int no1 = no;

String s = Integer.toString(no);

int d = s.length();

int arr[] =new int[no];

int i , sum;

for(i=d-1;i>=0;i--)

{

arr[i] = no1%10;

no1=no1/10;

}

i = d , sum =0;

while (sum <no)

{

sum =0

for(int j=1, j<=d,j++)

{

sum = sum+arr[i-j];

}

arr[i]=sum;

i++;

if (sum ==no)

System.out.println("The given number is a keith number");

else

System.out.println("The given number is not a Keith Number");

}

Output

In the above program, we have first declared and initialized a set of variables required in the program.

no = it will hold entered length.
no1= it will replicated value of no1 for digit calculation.
d= it will hold the number of digits.
sum = it will hold the summation of no. of term terms.
arr[]= is a array for holding all the terms of series.
i,j = will hold the numerical value to execute the loop.

Keith number is a term/entity which is repeated on a series when of a number is break down into the respective digits and add to get the desired number again.

After that take valuesin to an array.

Calculating the Keith Number from array we made.

Program to check Fascinating Number in Java

In this tutorial, we will learn to create a Java Program to check Fascinating Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Fascinating Number?

In Mathematics, any 3-digit number is said to be a fascinating when the base number is multiplied by 2 and 3 respectively and the outcome of the 2 multiplication are concatenated with base number and there is no repeated number in the concatenated number, i.e. from 1 to 9 all are occurred once in the number here. 0 are ignored in the final outcome number. If any number from 1 to 9 is repeated then that number is not a fascinating number

Java Program to check the number is fascinating number

In this program we would find the given number is fascinating number first will take the input from the user and check whether it is a3-digit number or not. If it’s not a 3-digit number then the program will be terminated. Then if the number is a 3-digit number then the program will continue and check the number. The fascinating number is a commonly asked question in coding tests of java.

For example, 192 to be checked

Then

192

192*2=384

192*3=576

“192” + “384” + “576” = 192384576

Here the above number doesn’t repeat any number hence it is a fascinating number.

import java.util.*;  
class Facinating
{  
Public static void main (String[] args)
	{
		Scanner sn = new Scanner(System.in);
		int num,n1,n2,flag,i,f;
		char ch,d;
		String s="";
		System.out.println("Enter any number of three or more digits ");
		num=sn.nextInt	();
		if(num<100)
		{
			System.out.println("Invalid Input");
			System.exit(0);
		}
		n1=num*2;
		n2=num*3;
		s=num+""+n1+""+n2;
		flag=1;
		for(d='0';d<='9';d++)
		{
			f=0;
			for(i=0;i<s.length();i++)
			{
				ch=s.charAt(i);
				if(d==ch)
				{
					f++;
				}
			}
			if(f!=1)
			{
				flag=0;
				break;
			}
		}
		if(flag==1)
		{
			System.out.println(num+"facinating number");
		}
		else
		{
			System.out.println(num+"is not a facinating number");
		}
	}
}

import java.util.*;

class Facinating

{

Public static void main (String[] args)

{

Scanner sn = new Scanner(System.in);

int num,n1,n2,flag,i,f;

char ch,d;

String s="";

System.out.println("Enter any number of three or more digits ");

num=sn.nextInt ();

if(num<100)

{

System.out.println("Invalid Input");

System.exit(0);

}

n1=num*2;

n2=num*3;

s=num+""+n1+""+n2;

flag=1;

for(d='0';d<='9';d++)

{

f=0;

for(i=0;i<s.length();i++)

{

ch=s.charAt(i);

if(d==ch)

{

f++;

}

if(f!=1)

{

flag=0;

break;

}

if(flag==1)

{

System.out.println(num+"facinating number");

}

else

{

System.out.println(num+"is not a facinating number");

}

Output

Program to check Tech Number in Java

In this tutorial, we will learn to create a Java Program to check Tech Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Tech Number.

A number is called a Tech number if an even number digit split into two halves(1/2) then square of the sum of those halves(1/2) is equal to the original number.

Example :->3025 So split 3025 into two halves

30.
25.
then = (30) +( 25)
= 55
=55*55.
=3025
So => 3025 is a tech number.

Program to check Tech Number in Java

In this program we would create a java program to find given number is a Tech number or not .First will take the input from the user and check whether it is Tech number or not. If it’s not then the program will show the output as it’s not a tech number.

// java program to find given number is a tech number.
import java.util.Scanner;

public class Tech_num {

   private static boolean Tech(int num) {

      // declare variables
      int no = num; // temprory store number
      int ct = 0; // store digits of  a number
      int fH = 0; // first half of the number
      int lH = 0; // last half of the number
      int sum = 0;

      // counting  digits
      while(no != 0) {
         no /= 10;
	 ct++;
      }

      // if number of digits is not even
      // then number is not tech number
      if(ct%2!=0) return false;

      // calculate halves
      fH = num / (int)Math.pow(10, ct/2);
      lH = num % (int)Math.pow(10, ct/2);

      // calculate sum of halves 
      sum = fH + lH;

      // check number is equal to
      // square of sum or not
      if(sum*sum == num) 
            return true;
      return false;
   }

   public static void main(String[] args) 
   {
      int number = 0;

      // declare variable and take value from user at run time.
      Scanner scan =  new Scanner(System.in);
      System.out.print("Enter a four digit number ");
      number = scan.nextInt();

      // check the number is tech number or not
      if(Tech(number))
      System.out.println(number+" is a" + " tech number");
      else
      System.out.println(number+" is not a"  + " tech number");
   }
}

// java program to find given number is a tech number.

import java.util.Scanner;

public class Tech_num {

private static boolean Tech(int num) {

// declare variables

int no = num; // temprory store number

int ct = 0; // store digits of a number

int fH = 0; // first half of the number

int lH = 0; // last half of the number

int sum = 0;

// counting digits

while(no != 0) {

no /= 10;

ct++;

}

// if number of digits is not even

// then number is not tech number

if(ct%2!=0) return false;

// calculate halves

fH = num / (int)Math.pow(10, ct/2);

lH = num % (int)Math.pow(10, ct/2);

// calculate sum of halves

sum = fH + lH;

// check number is equal to

// square of sum or not

if(sum*sum == num)

return true;

return false;

}

public static void main(String[] args)

{

int number = 0;

// declare variable and take value from user at run time.

Scanner scan = new Scanner(System.in);

System.out.print("Enter a four digit number ");

number = scan.nextInt();

// check the number is tech number or not

if(Tech(number))

System.out.println(number+" is a" + " tech number");

else

System.out.println(number+" is not a" + " tech number");

}

Output

Tech Number

Not a Tech Number.

In the above program, we have first declared and initialized a set variables required in the program.

num,numberand no = it will hold entered number.
fH and Lh = it will hold first half and last half of a number.
ct= finding digit of a number.
sum= sum of digit.

After that we take a number from user and find given number is a Tech number or not

after taking values we will pass number to function Tech() where we check multiple conditions as shown in image below.

check entered number is a four digit number or not. if given number is a four digit nmber then we break number into two half first two in hF variable and second two in lF variable

and these two in variable sum where we find square of their addition.

and then compare square of sum equals to the given number

then number is a Tech number otherwise it is not a tech number.

Program to check Sunny Number in Java

In this tutorial, we will learn to create a Java Program to check Sunny Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Sunny Number.

Sunny number is a number,if next number to a given number is a perfect square.

For Example=> 80 is a Sunny Number because 81 is a perfect square of 9.

Program to check Sunny Number in Java

In this program we would find given number is a Sunny number or not .first of we would take a value from user and find the Sunny number.let have a look at the code.

// java program to find given number is a Sunny number or not..
import java.util.Scanner;
public class Sunny {

   // Function to check the Sunny number
   public static boolean Sunny_no(int num)
   {
      if(Math.sqrt(num+1)%1 == 0)
      return true;
      else 
      return false;
   }

   // main method
   public static void main(String[] args) 
   {      // declare variables and tale value from user.
      int number = 0;
      boolean result = false;
      Scanner scan = new Scanner(System.in);
      System.out.print("Enter any integer value");
      number = scan.nextInt();

      // check number is Sunny number or not
      result = Sunny_no(number);

      // display result
      if(result)
          System.out.println(number +" is a Sunny number.");
      else
          System.out.println(number +" is not a Sunny number.");
   }
}

// java program to find given number is a Sunny number or not..

import java.util.Scanner;

public class Sunny {

// Function to check the Sunny number

public static boolean Sunny_no(int num)

{

if(Math.sqrt(num+1)%1 == 0)

return true;

else

return false;

}

// main method

public static void main(String[] args)

{ // declare variables and tale value from user.

int number = 0;

boolean result = false;

Scanner scan = new Scanner(System.in);

System.out.print("Enter any integer value");

number = scan.nextInt();

// check number is Sunny number or not

result = Sunny_no(number);

// display result

if(result)

System.out.println(number +" is a Sunny number.");

else

System.out.println(number +" is not a Sunny number.");

}

Output

Sunny Number.

Not a Sunny Number.

In the above program, we have first declared and initialized a set variables required in the program.

num,numberand= it will hold entered number.
result it will hold result it means number is a sunny or not.

After that we take a number from user and find given number is a Sunny number or not

and pass this number to Sunny_no() function where we check condition for sunny number or we cans say condition for Perfect square where we add one to the number to check it is Sunny Number or not.

Function return value true if number is Perfect square

else return false and we will store the return value in variable result.

if value of result is true number is Sunny and if value of result if false number is not a Sunny number.

Program to check Peterson Number in Java

In this tutorial, we will learn to create a Java Program to check Peterson Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Peterson Number in Java

A number is called Peterson Number if sum of its factorials of each digit is equal to the sum of the number itself.

145 = 5! + 4! + 1!
145 = 120 + 24 +1
145 = 145

Explanation: factorial of
!5 = 5*4*3*2*1=120.
!4=4*3*2*1=24.
!1=1.
So sum of its factorial gives the number itself called Peterson.

Program to check Peterson Number in Java.

In this our program we will find given number is a Peterson number or not in using java. We would first declared and initialized the required variables. Next, we would prompt user to input the a number.Later we find number is Peterson number or not let’s have a look at the code.

// Java program to find given number is Peterson number or not..
import java.util.Scanner;
public class Peterson{
//
    static long[] factorial = new long[] { 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880};
    public static void main(String args[])
    {
       // Declaring and taking values form user..
        Scanner scan = new Scanner(System.in);
        System.out.print("Enter any number: ");
        int number = scan.nextInt();
        // checking condition for Peterson number..
        if (Peterson(number))
            System.out.println(number+ " is a Peterson number.");
        else
            System.out.println(number + " is not a Peterson number.");
    }
    //Creating a method to find Peterson number
        static boolean Peterson(int no)
    {
        int number = no;
        int sum = 0;
        while (no > 0)
        {
            //we get the last digit of the number
            int lastDigit = no % 10;
            sum += factorial[lastDigit];
            no = no / 10;
        }
        return (sum == number);
    }
}

// Java program to find given number is Peterson number or not..

import java.util.Scanner;

public class Peterson{

static long[] factorial = new long[] { 1, 1, 2, 6, 24, 120, 720, 5040, 40320, 362880};

public static void main(String args[])

{

// Declaring and taking values form user..

Scanner scan = new Scanner(System.in);

System.out.print("Enter any number: ");

int number = scan.nextInt();

// checking condition for Peterson number..

if (Peterson(number))

System.out.println(number+ " is a Peterson number.");

else

System.out.println(number + " is not a Peterson number.");

}

//Creating a method to find Peterson number

static boolean Peterson(int no)

{

int number = no;

int sum = 0;

while (no > 0)

{

//we get the last digit of the number

int lastDigit = no % 10;

sum += factorial[lastDigit];

no = no / 10;

}

return (sum == number);

}

Output

Peterson Number

Not a Peterson number

In the above program, we have first declared and initialized a set variables required in the program.

number= it will hold entered number.
sum= it will hold sum of digit
no = it will also hold value of number
lastdigit= last digit of a number.

After declaring variables in the next statement user will be prompted to enter a value and which will be assigned to variable ‘number’.

And after that we check condition for Peterson number if condition get satisfied it means the given number is Peterson number if not then it is not Peterson number.

Logic Behind of Finding Peterson Number.

First we take and initialize a number to (number).
Find the last digit (last digit) of the given number by user.
Find the factorial of all the digits.
Add the factorial of all digits to (sum) variable as shown in image below.
Repeat steps until find all the factors of given number.
Compare sum with number if( sum==number). If they are equal, the given number is Peterson,

else not.

Program to check Automorphic Number in Java

In this tutorial, we will learn to create a Java Program to check Automorphic Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is an automorphic number?

A number is called an automorphic number if square of the number ends with the same number itself as shown in example below.

Example. 5,6, 25, 76 etc are automorphic numbers.

Program to check Automorphic Number in Java

In this our program we will find given number is a automorphic number or not in using java. We would first declared and initialized the required variables. Next, we would prompt user to input the a number.Later we find number is automorphic number or not let’s have a look at the code.

// Java program to find Automorphic number
import java.util.Scanner;
 
public class Automorphic_number {
 
    public static void main(String args[]){
      // Decalring avriables taking values form user..
        Scanner in = new Scanner(System.in);
        System.out.println("Enter any number");
        int number = in.nextInt();
 
        int c=0, square = number*number;// squaring values
        int temp =number; // making copy of number
 
        //calucalting values
        while(temp>0)
        {
            c++;
            temp=temp/10;
        }
       // finding last digit or value
        int lastDigits = (int)(square%(Math.pow(10,c)));
        
        
    // comparing last digit to roginal number
        if(number == lastDigits)
            System.out.println(number+" is a Automorphic number");
        else
            System.out.println(number +" is Not an Automorphic number");
    }
}

// Java program to find Automorphic number

import java.util.Scanner;

public class Automorphic_number {

public static void main(String args[]){

// Decalring avriables taking values form user..

Scanner in = new Scanner(System.in);

System.out.println("Enter any number");

int number = in.nextInt();

int c=0, square = number*number;// squaring values

int temp =number; // making copy of number

//calucalting values

while(temp>0)

{

c++;

temp=temp/10;

}

// finding last digit or value

int lastDigits = (int)(square%(Math.pow(10,c)));

// comparing last digit to roginal number

if(number == lastDigits)

System.out.println(number+" is a Automorphic number");

else

System.out.println(number +" is Not an Automorphic number");

}

Output

Automorphic number

Not a Automorphic Number.

In the above program, we have first declared and initialized a set variables required in the program.

number= it will hold entered number.
temp= ti will actual copy of a number.
lastDigits=it will hold last digit of square of given number.
square=it will hols square of given number.

After declaring variables in the next statement user will be prompted to enter a value and which will be assigned to variable ‘number’.

And after that we will find square of that value and after that we will find last two digits of given number and making the copy of original number as shown in picture below.

After that we will find last two digits of a number.

then check condition for Automorphic number if condition get satisfied it means the given number is Automorphic number if not then it is not Automorphic number.

And finally we print the given number is Automorphic Number or not.

Program to check Unique Number In Java

In this tutorial, we will learn to create a Program to check Unique Number in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Unique Number.

The number is called a unique if there is no repeated digits in the given number.

For Example:=> 20, 56, 98 are Unique Number
But => “22,99,121,100” are not unique because they contain repeated digits in them.

Program to check Unique Number In Java

In this program we would find the given number is a Unique number or not .first of all we would take a value from user and find the Unique number.let have a look at the code.

// java program to find unique number..
import java.util.Scanner;  
public class Unique_Num  
{  
public static void main(String args[])  
{  
//Decalring variabels     
int rem, rem1, number, num1, num2, count = 0;  
Scanner sc = new Scanner(System.in);  
System.out.print("Enter any number ");  
number = sc.nextInt();  
//num1 and num2 are temporary variable  
num1 = number;  
num2 = number;  
//iterate over all digits of the number  
while (num1 > 0)  
{  
//detrmins the last digit of the number      
rem = num1 % 10;  
while (num2 > 0)  
{  
//finds the last digit  
rem1 = num2 % 10;  
//comparing the last digit  
if (rem == rem1)  
{  
//increments the count variable by 1      
count++;  
}  
//removes the last digit from the number  
num2 = num2 / 10;  
}  
//removes the last digit from the number  
num1 = num1 / 10;  
}  
if (count == 1)  
{  
System.out.println("The number is unique.");  
}  
else  
{  
System.out.println("The number is not unique.");  
}  
}  
}

// java program to find unique number..

import java.util.Scanner;

public class Unique_Num

{

public static void main(String args[])

{

//Decalring variabels

int rem, rem1, number, num1, num2, count = 0;

Scanner sc = new Scanner(System.in);

System.out.print("Enter any number ");

number = sc.nextInt();

//num1 and num2 are temporary variable

num1 = number;

num2 = number;

//iterate over all digits of the number

while (num1 > 0)

{

//detrmins the last digit of the number

rem = num1 % 10;

while (num2 > 0)

{

//finds the last digit

rem1 = num2 % 10;

//comparing the last digit

if (rem == rem1)

{

//increments the count variable by 1

count++;

}

//removes the last digit from the number

num2 = num2 / 10;

}

//removes the last digit from the number

num1 = num1 / 10;

}

if (count == 1)

{

System.out.println("The number is unique.");

}

else

{

System.out.println("The number is not unique.");

}

Output

Unique Number

Not a Unique Number.

In the above program, we have first declared and initialized a set variables required in the program.

number= it will hold entered number.
num1,num2=it will hold temporary number.
count= it will hold repetition number,
rem,rem1- it will hold last digit of a numbers.

After that we take a number from user and find given number is a Unique number or not.

Steps to check given number is unique or not:

take a value from the user in number variable.
Break digit and find the last digit o the number.
Check each digit in number with the last digit.
If the digit repeated more than one time, the number is not unique.
Else, remove the last digit of the number.
Repeat steps until the number becomes zero.

The number is called a unique if there is no repeated digits in the given number.

else it is not a unique number.

Program to check Nelson Number in Java

In this tutorial, we will learn to create a Java Program to check Nelson Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Nelson Number

The number “111” is called “Nelson Number” after the name of sir “Admiral Nelson“,because he had only had “One Eye, One Arm, One Leg” at the end of his life.Double of Nelson number called Double Nelson (222), triple Nelson (333), and so on..

Program to check Nelson Number in Java

In this our program we will find given number is a Nelson number or not in using java programming. We would first declared and initialized the required variables. Next, we would prompt user to input the a number.Later we find number is Nelson number or not let’s have a look at the code.

//Java Program to fin Nelson number
import java.util.Scanner;

public class Nelson_Number {

    public static void main(String[] args) {
// Declaring variable and taking values...
    	Scanner in = new Scanner(System.in);
    	System.out.println("Please enter a number");
    	int number=in.nextInt();
     // Checking condition for nelson number
    	if(number==111 || number==222 || number==333 || number==444 ||
    	   number==555 || number==666 || number==777 || number==888 || number==999)
    	{
        System.out.println("It is Nelson Number "+number);
        }
        else
        {
            System.out.println("It is Not a Nelson Number"+number);
    	} 
    }
}

//Java Program to fin Nelson number

import java.util.Scanner;

public class Nelson_Number {

public static void main(String[] args) {

// Declaring variable and taking values...

Scanner in = new Scanner(System.in);

System.out.println("Please enter a number");

int number=in.nextInt();

// Checking condition for nelson number

if(number==111 || number==222 || number==333 || number==444 ||

number==555 || number==666 || number==777 || number==888 || number==999)

{

System.out.println("It is Nelson Number "+number);

}

else

{

System.out.println("It is Not a Nelson Number"+number);

}

Output

Nelson number.

Not a nelson number.

In the above program, we have first declared and initialized a set variables required in the program.

number= it will hold entered number.

After declaring variables in the next statement user will be prompted to enter a value and which will be assigned to variable ‘number’.

And after that we check condition for Nelson number if condition get satisfied it means the given number is Nelson number if not then it is not Nelson number.

Condition for Nelson number.

If the above Condition satisfied the given number by user is a Nelson number.

If not then the given number is not a Nelson number.

Program to check Kaprekar Number In Java

In this tutorial, we will learn to create a Java Program to check Kaprekar Numbers in Java using Java programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following Java programming topics:

Java Operators.
Basic Input and Output function in Java.
Class and Object in Java.
Basic Java programming.
If-else statements in Java.
For loop in Java.

What is Kaprekar Number.

Capricorn or Kaprekar number is a number whose square is divided into two parts and add the additions of parts is equal to the number.

Example of “kaprekar numbers”:- 45
The square of 45 = 2025
20 + 25 = 45, so 45 is a kaprekar number.

Program to check Kaprekar Number In Java

In this program we would find the given number is a Kaprekar or Capricorn number or not.first of all we would take a value from user and find the Capricorn number.let have a look at the code.

// java program to find Kaprekar number..
import java.util.Scanner;
public class Kaprekar_no
{
   public static boolean Kaprekar(int num) 
   {
      // declare variable and take value from user..
      int sqr = 0;
      int temp = 0;
      int cDigit = 0;
      int fH = 0;
      int sH = 0;
      int sum = 0;
      // calculate square of number..
      sqr = num * num;
      // count number of digits ..
      temp =sqr;
      while(temp!=0)
      {
         cDigit++;
         temp /= 10; 
      }
      // divide square into two parts and 
      // check it's sum is equal to the number?
      for(int i=cDigit-1; i>0; i--)
      {
          // find first part
         fH = sqr / (int)Math.pow(10, i);
         // find second part
         sH = sqr % (int)Math.pow(10, i);
         // check have any part only 0
         if(fH == 0 || sH == 0)
         	continue;
         // find sum value
         sum = fH + sH;
         // compare sum and number
         if( sum == num )
         return true;
      }
      return false;
   }
   public static void main(String[] args) {
      // declare variables
      int no = 0;
      // read the input 
      Scanner scan =  new Scanner(System.in);
      System.out.print("Enter an any number");
      no = scan.nextInt();
      // check the number is kaprekar number or not
      if(Kaprekar(no))
      System.out.println(no+" is a"	+"kaprekar number");
      else
      System.out.println(no+" is not a"	+ "kaprekar number");
      // close Scanner class object
      scan.close();
   }
}

// java program to find Kaprekar number..

import java.util.Scanner;

public class Kaprekar_no

{

public static boolean Kaprekar(int num)

{

// declare variable and take value from user..

int sqr = 0;

int temp = 0;

int cDigit = 0;

int fH = 0;

int sH = 0;

int sum = 0;

// calculate square of number..

sqr = num * num;

// count number of digits ..

temp =sqr;

while(temp!=0)

{

cDigit++;

temp /= 10;

}

// divide square into two parts and

// check it's sum is equal to the number?

for(int i=cDigit-1; i>0; i--)

{

// find first part

fH = sqr / (int)Math.pow(10, i);

// find second part

sH = sqr % (int)Math.pow(10, i);

// check have any part only 0

if(fH == 0 || sH == 0)

continue;

// find sum value

sum = fH + sH;

// compare sum and number

if( sum == num )

return true;

}

return false;

}

public static void main(String[] args) {

// declare variables

int no = 0;

// read the input

Scanner scan = new Scanner(System.in);

System.out.print("Enter an any number");

no = scan.nextInt();

// check the number is kaprekar number or not

if(Kaprekar(no))

System.out.println(no+" is a" +"kaprekar number");

else

System.out.println(no+" is not a" + "kaprekar number");

// close Scanner class object

scan.close();

}

Output

Kaprekar Number.

Not a Kaprekar Number.

In the above program, we have first declared and initialized a set variables required in the program.

no= it will hold entered number.
temp= it will hold temp the value of a number.
sqr= it wil hold square of a number.
cDigit= it will count digit.
fH and sH= fH holds first half and sH holds Second half.
sum =it will hold sum of values.

After that we take a number from user and find given number is a Kaprekar number or not

after getting a value from user we will pass the number to function if(Kaprekar(no)) where we will check condition for Kaprekar number that given number is Kaprekar number or not.

Procedure that check the given number is kaprekar number or not.

1) Take a number from user.
2) Find the square of a number.
3) Count all the digit of a squared number.
4) Iterator variable i start from digits of square – 1.
5) Ge first half, by dividing the square value by 10.
6) And second part as remainder value after dividing 10.
7) Check value of half’s if any part having only 0, if found skip the iteration if not.
8) Calculate sum of hF+sH.
9) Comparing sum and number,

if both are equal then function returns true and if not function returns False.

and finally we will print number is Kaprekar or not.