Category Archives: C++ Programs

c plus plus programs

C++ Program to perform addition, subtraction, multiplication and division using Switch

C++ Program to Perform Addition, Subtraction, Multiplication, and Division using Switch

In this tutorial, we will learn to create a C++ program. After that will perform Addition, Subtraction, Multiplication, and Division in C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ Programming.

Program for performing the Addition, Subtraction, Multiplication, and Division:-

Every Programming language is having many predefined functions for arithmetic operations. In the C++ programming language, we will do the Addition, Subtraction, Multiplication, and Division operations with the help of Arithmetic operators using the switch case.

Algorithm for procedure:-

1. Declaring the variables for the program.

2. Taking input operator for operations.

2. Taking the input numbers from the user in number format.

3. Adding the numbers and storing it in a variable.

4. Subtracting the numbers and storing it in a variable.

5. Multiplying the numbers and storing it in a variable. 

6. Dividing the numbers and storing it in a variable.

7. Printing the Outputs. 

8. End program.

1. Declaring the variables for the program.

2. Taking input operator for operations.

2. Taking the input numbers from the user in number format.

3. Adding the numbers and storing it in a variable.

4. Subtracting the numbers and storing it in a variable.

5. Multiplying the numbers and storing it in a variable.

6. Dividing the numbers and storing it in a variable.

7. Printing the Outputs.

8. End program.

Program for Addition, Subtraction, Multiplication and Division:-

/* C++ Program to Perform Addition, Subtraction, Multiplication, 
and Division of Two Numbers using switch case*/ 

# include <iostream>
using namespace std;

int main() 
{
    //declaring the requred variables for the program.
    char op;
    float no1, no2;
    
    
    //taking input symbol from the user for performing the calculations
    cout << "Enter operator: +, -, *, /: ";
    cin >> op;
    
    //Taking the two numbers for calculations
    cout << "Enter two operands/ numbers for operations: ";
    cin >> no1 >> no2;

    switch(op) {
        case '+':
            //Priniting the add operation for the values.
            cout << no1 << " + " << no2 << " = " << no1 + no2;
            break;

        case '-':
            //Priniting the subtract operation for the values.
            cout << no1 << " - " << no2 << " = " << no1 - no2;
            break;

        case '*':
            //Priniting the multiply operation for the values.
            cout << no1 << " * " << no2 << " = " << no1 * no2;
            break;

        case '/':
            //Priniting the divide operation for the values.
            cout << no1 << " / " << no2 << " = " << no1 / no2;
            break;

        default:
            // If the operator is other than +, -, * or /, error message is shown
            cout << "Error! operator is not correct";
            break;
    }

    return 0;
}

/* C++ Program to Perform Addition, Subtraction, Multiplication,

and Division of Two Numbers using switch case*/

# include <iostream>

using namespace std;

int main()

{

//declaring the requred variables for the program.

char op;

float no1, no2;

//taking input symbol from the user for performing the calculations

cout << "Enter operator: +, -, *, /: ";

cin >> op;

//Taking the two numbers for calculations

cout << "Enter two operands/ numbers for operations: ";

cin >> no1 >> no2;

switch(op) {

case '+':

//Priniting the add operation for the values.

cout << no1 << " + " << no2 << " = " << no1 + no2;

break;

case '-':

//Priniting the subtract operation for the values.

cout << no1 << " - " << no2 << " = " << no1 - no2;

break;

case '*':

//Priniting the multiply operation for the values.

cout << no1 << " * " << no2 << " = " << no1 * no2;

break;

case '/':

//Priniting the divide operation for the values.

cout << no1 << " / " << no2 << " = " << no1 / no2;

break;

default:

// If the operator is other than +, -, * or /, error message is shown

cout << "Error! operator is not correct";

break;

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no1= it will hold the input number value from the user.
no2 = it will hold the input number value from the user.
op = it will hold the character value for the operator.

Taking Input operator from the user.

Taking input number from the user.

Program code for operations.

C++ Program to Perform Addition, Subtraction, Multiplication and Division

C++ Program to Perform Addition, Subtraction, Multiplication, and Division

In this tutorial, we will learn to create a C++ program. After that will perform Addition, Subtraction, Multiplication, and Division in C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ Programming.

Program for performing the Addition, Subtraction, Multiplication, and Division:-

In today’s tutorial, we will create a program. That will do the Addition, Subtraction, Multiplication, and Division operations with the help of Arithmetic operators in C++ programming.

Algorithm for Addition, Subtraction, Multiplication, and Division:-

1. Declaring the variables for the program.

2. Taking the input numbers from the user in number format.

3. Adding the numbers and storing it in a variable.

4. Subtracting the numbers and storing it in a variable.

5. Multiplying the numbers and storing it in a variable. 

6. Dividing the numbers and storing it in a variable.

7. Printing the Outputs. 

8. End program.

1. Declaring the variables for the program.

2. Taking the input numbers from the user in number format.

3. Adding the numbers and storing it in a variable.

4. Subtracting the numbers and storing it in a variable.

5. Multiplying the numbers and storing it in a variable.

6. Dividing the numbers and storing it in a variable.

7. Printing the Outputs.

8. End program.

Program for Addition, Subtraction, Multiplication, and Division:-

/* C++ Program to Perform Addition, Subtraction, Multiplication, 
and Division of Two Numbers */ 

#include <iostream> 
using namespace std; 
int main() 
{ 
    //Declaring the variables for the program 
    int fno, sno, multiplyy,addd,subb,dividee; 
    
    //Taking input numbers from the user for multiplicaiton of the two values. 
    cout << "Enter two numbers: "; 
    cin >> fno >> sno; 
    
    // sum of two numbers in stored in variable addd 
    addd = fno + sno; 
    // subtracton of two numbers in stored in variable subb 
    subb = fno - sno; 
    // multiplicaiton of two numbers in stored in variable multiplyy
    multiplyy = fno * sno; 
    // division of two numbers in stored in variable dividee
    dividee = fno / sno; 
    
    // Prints addition of two numbers 
    cout << "addition of two numbers " << fno << " + " << sno << " = " << addd <<endl; 
    // Prints subtraction of two numbers 
    cout << "subtraction of two numbers " << fno << " - " << sno << " = " << subb <<endl; 
    // Prints multiplication of two numbers 
    cout << "multiplication of two numbers " << fno << " * " << sno << " = " << multiplyy <<endl; 
    // Prints division of two numbers 
    cout << "division of two numbers " << fno << " / " << sno << " = " << dividee <<endl; 
    return 0; 
    
}

/* C++ Program to Perform Addition, Subtraction, Multiplication,

and Division of Two Numbers */

#include <iostream>

using namespace std;

int main()

{

//Declaring the variables for the program

int fno, sno, multiplyy,addd,subb,dividee;

//Taking input numbers from the user for multiplicaiton of the two values.

cout << "Enter two numbers: ";

cin >> fno >> sno;

// sum of two numbers in stored in variable addd

addd = fno + sno;

// subtracton of two numbers in stored in variable subb

subb = fno - sno;

// multiplicaiton of two numbers in stored in variable multiplyy

multiplyy = fno * sno;

// division of two numbers in stored in variable dividee

dividee = fno / sno;

// Prints addition of two numbers

cout << "addition of two numbers " << fno << " + " << sno << " = " << addd <<endl;

// Prints subtraction of two numbers

cout << "subtraction of two numbers " << fno << " - " << sno << " = " << subb <<endl;

// Prints multiplication of two numbers

cout << "multiplication of two numbers " << fno << " * " << sno << " = " << multiplyy <<endl;

// Prints division of two numbers

cout << "division of two numbers " << fno << " / " << sno << " = " << dividee <<endl;

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

fno = it will hold the input number value from the user.
sno = it will hold the input number value from the user.
addd = it will hold the added value of the numbers.
subb= it will hold the subtraction value of the numbers.

Taking Input numbers from the user.

Perform Addition, Subtraction, Multiplication, and Division of two numbers.

Printing the output.

C++ Programs to Find LCM of Two Numbers

In this tutorial, we will learn to create a c++ program that will find LCM of two numbers using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators.
Looping statements
While loop.
if else Statement.
Basic input/output.
Basic c++ programming.

What Is LCM?

LCM is a method to finding the smallest possible multiplication of two or more numbers. LCM of a numbers is divisible by both or more numbers. For example, LCM of 5 ,4 and 20 is 20.

C++ Programs to Find LCM of Two Numbers.

In this program you will learn to find LCM of two given number using while loop. We would first declared and initialized the required variables. Next, we would prompt user to input two numbers.Later we will find the or given number.

#include <iostream>
using namespace std;
int main() {
    int num1, num2, max;
    cout<<"Enter two positive integers: "; // taking two numbers
    cin>>num1>>num2;
    max = (num1 > num2) ? num1 : num2; // finding bigger number
    while (1) 
    {
        if (max % num1 == 0 && max % num2 == 0) // condition for lcm
        {
        cout<<"The LCM of "<<num1<<" and "<<num2 <<" is "<<max; break;
        }
        ++max;
    }
    return 0;
}

#include <iostream>

using namespace std;

int main() {

int num1, num2, max;

cout<<"Enter two positive integers: "; // taking two numbers

cin>>num1>>num2;

max = (num1 > num2) ? num1 : num2; // finding bigger number

while (1)

{

if (max % num1 == 0 && max % num2 == 0) // condition for lcm

{

cout<<"The LCM of "<<num1<<" and "<<num2 <<" is "<<max; break;

}

++max;

}

return 0;

}

Output

In the above program, we have first declared and initialized a set variables required in the program.

num1 =It will hold first number given by user.
num2 =It will hold second number given by user.
max=This will find biggest among the number.

Let see the step by step method of finding LCM.

LCM of two given number, is as follows:

1: user will be prompted to enter two the positive integer values no1 and no2.

2: Storing the biggest value of num1 & num2 in max variable.3: On checking condition whether the max is divisible by both variables num1 and num2 loop will iterate until it will find a value which divisible by both number.

4: If variable max is divisible,Then display max as the LCM of these two numbers.

5: Else, the value of max is increased, and go to step 3 again and again.
6: Stop the program.

LCM stands for Least Common Multiple (LCM). It’s the smallest possible number that is completely divisible by both integer’s num1 and num2, without leaving any remainder means zero(0). It is also known as the Lowest Common Multiple.

C++ Program to Find GCD

In this tutorial, we will learn to create a C++ program that will find GCD or HCF of two number using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators.
General C programming.
Basic input/output.
Looping statements
While loop.
if else Statement.

What Is GCD?

GCD(Greatest Common Divisor) or HCF (Highest Common Factor) . When we finding the factor of two numbers, Highest Common Factor of numbers is the Largest factor that divides these two numbers. The greatest factor found from the common factors is called the HCF. It is also called the Greatest common factor.

C++ Program to Find GCD.

In this program we will find GCD of two given number using For loop. We would first declared and initialized the required variables. Next, we would prompt user to input two numbers.Later we will find the GCD of given number.

#include <iostream>
using namespace std;
int main()
{
    int num1, num2, i, gcd=1; // declaring variables.

    cout<<"Enter two positive integers: ";
    cin>>num1>>num2; // taking values from user.

    for(i=1; i <= num1 && i <= num2; ++i) // iteration for condition.
    {
        if(num1%i==0 && num2%i==0) // Checking factor of number
            gcd = i;
    }
    cout<<"G.C.D of "<<num1 <<" and "<<num2<<" is "<<gcd; // printing values 
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

int num1, num2, i, gcd=1; // declaring variables.

cout<<"Enter two positive integers: ";

cin>>num1>>num2; // taking values from user.

for(i=1; i <= num1 && i <= num2; ++i) // iteration for condition.

{

if(num1%i==0 && num2%i==0) // Checking factor of number

gcd = i;

}

cout<<"G.C.D of "<<num1 <<" and "<<num2<<" is "<<gcd; // printing values

return 0;

}

Output

C++ Program to Find GCD

In the above program, we have first declared and initialized a set variables required in the program.

num1 =It will hold first number given by user.
num2 =It will hold second number given by user.
gcd= it will hold Greatest common divisor.

Let see the step by step method of finding GCD.

GCD of two number is :
1: user will be prompted to enter two the positive integer values num1 and num2.
2: Storing the given value in variable num1 & num2 as shown below.

3: Initializethe value of gcd to one gcd=1.

4:Within the loop we check if i divide completely these two numbers num1 and num2.
i.e. i exactly divides the given numbers and remainder is equal to zero, then the value of i is assigned to gcd variable.
5:When the loop is completed, the greatest common divisor of two numbers is stored in variable gcd.
6: At lst we will print the value of gcd .

The of two integers is the greatest integer that can exactly divide both numbers (with a remainder ==0) .

C++ Programs to Write BuzzFizz Program

In this tutorial, we will learn to create a C++ program that will find BUZZ FIZZ numbers using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators
Basic C++ programming.
Basic input/output.
Looping statements.
For Loop.
If else statement.

What Is Buzz Fizz?

The concept of Buzz and Fizz is that if integers value between 1 to given number,we will print “Fizz” if an integer number is divisible by 3, “Buzz” if an integer number is divisible by 5, and “FizzBuzz” if an integer number is divisible by both 3 and 5.

Example:

In a program that shows the numbers from 1 to number(suppose 15) .If number is a multiple of ‘3 ’ we print “Fizz” instead of if multiples of ‘5’ we print “Buzz” and if multiple of both 3 and 5 then we print “Fizz Buzz”.Following sereis will shoe Fizz anf Buzz in place or multiples.Have a look.
1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14,
Fizz Buzz.

Buzz Fizz Program in C++.

In this program we will print find Buzz Fizz using for loop. We would first declared and initialized the required variables. Next, we would prompt user to input the number of terms. Later we will find Buzz Fizz series of specified number of terms.

#include <iostream>
using namespace std;
int main()
 { 
     int i;
    for(i=1;i<=20;i++) // iterate loop till 20 values
    {
        if((i%3 == 0) && (i%5==0)) // finding FIZZBUzz
            cout<<"FizzBuzz";
        else if(i%3 == 0)          //Finding FIzz 
            cout<<"Fizz ";
        else if(i%5 == 0)          //Finding Buzz   
            cout<<"Buzz ";
        else
            cout<<i<<" ";          //printing numbers
     }
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

int i;

for(i=1;i<=20;i++) // iterate loop till 20 values

{

if((i%3 == 0) && (i%5==0)) // finding FIZZBUzz

cout<<"FizzBuzz";

else if(i%3 == 0) //Finding FIzz

cout<<"Fizz ";

else if(i%5 == 0) //Finding Buzz

cout<<"Buzz ";

else

cout<<i<<" "; //printing numbers

}

return 0;

}

Output

In the above program, we have first declared and initialized a set variables required in the program.

i = for iteration of loop.

In our program we will print number from 1 to 20. If number with in series is multiple of 3 and 5, we print “FizzBuzz” instead of the number. as you can see in image below.

Andif number is multiple of 3, print “Fizz” instead of the number.

And in final case if numbers which are multiples of 5, print “Buzz” instead of the number.

And in else condition when number is not multiple of 3 and 5 we simply print the number .So in this program we run loop from 1- 20.the final out come series is look like this.

C++ Program to Calculate Sum of Natural Numbers

In this tutorial, we will learn to create a C++ program that will find Sum of N Natural Numbers using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators.
looping statements.
Basic input/output.
Basic c++ programming.

What Is Natural Number?

Simply all the counting numbers {…-3,-2-1,0,1, 2, 3, …} are commonly called natural numbers.

Natural numbers As such, it is a whole, non-negative are all number 1, 2, 3, 4,5,6,7,8,9,10… They are usually counting number and they will continue to infinity.while Whole number are all natural numbers including 0.

C++ Program to Calculate Sum of Natural Numbers

Firstly we declare required header file and variable and also initiates required values in variable. Next we take value from user at run time and then after we will find the sum of all natural number to given value.

#include <iostream>
using namespace std;

int main() {
    int num, sum = 0; // declaring variables

    cout << "Enter any positive integer: ";
    cin >> num; // taking number from user.

    for (int i = 1; i <= num; ++i) // calculating sum of all natural number
   {
        sum += i;
    }

    cout << "Sum of:"<<num <<" natural number is= "<< sum;
    return 0;
}

#include <iostream>

using namespace std;

int main() {

int num, sum = 0; // declaring variables

cout << "Enter any positive integer: ";

cin >> num; // taking number from user.

for (int i = 1; i <= num; ++i) // calculating sum of all natural number

{

sum += i;

}

cout << "Sum of:"<<num <<" natural number is= "<< sum;

return 0;

}

Output

In the above program, we have first declared and initialized a set variables required in the program.

i= for iteration of loop.
num=to take value from user.
sum = for calculating sum of natural number.

In this program first we take a value from user,

After that in this Program we add all natural number from 1 to 10.

- The first we will create an integer variable i,num and sum.
- then, we use For Loop to iterate between i=1 to i<=10 and
- Within the For loop, we add all i values in variable sum. sum+=i.
- In our program we calculate sum of natural value from 1- 10.
- At last we print the sum of 10 natural values.
that’s all fro this post thank-you.

C++ Programs to Calculate Sum Of Digits

C++ Program to Print Sum of Digits

In this tutorial, we will learn to create a C++ program that will Print Sum of digits in a given Number using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
While loop in C++ programming.
Conditional Statements in C++ programming.
Arithmetic operations in C++ Programming.

Program to Print Sum of digits in a given Number

In c++ programming, we will make a program in today’s tutorial. We will take integer input from the user and find Sum of digits in a given number with the help of a program.

With the help of this program, we can Print Sum of digits in a given number.

Algorithm:-

1. Declaring the variables required for the program.

2. Taking the input number from the user for the program.

3. Calculating the total number of digits in the numbers.

4. Calculating the sum of all the numbers in the given number.

5. Printing the result numbers.

6. End Program

1. Declaring the variables required for the program.

2. Taking the input number from the user for the program.

3. Calculating the total number of digits in the numbers.

4. Calculating the sum of all the numbers in the given number.

5. Printing the result numbers.

6. End Program

Program to Print Sum of digits in a given number:-

#include <iostream>  
using namespace std;  
int main()  
{  
    //declaring the variables required for the program
    int n,sum=0,m;  
    //n = it will hold the integer value for number input from the user
    //sum = it will hold the integer value for sum of digits
    //it will hold the integer value for
    //taking input number from the user
    cout<<"Enter a number: ";    
    //scanning the input number from the user
    cin>>n;    
    //calculating the sum of the number 
    //of digits of the given number
    while(n>0)    
    {    
        m=n%10;    
        sum=sum+m;    
        n=n/10;    
    }    
    //printing the sum of digits of given input
    cout<<"Sum is= "<<sum<<endl;    
    return 0;  
}

#include <iostream>

using namespace std;

int main()

{

//declaring the variables required for the program

int n,sum=0,m;

//n = it will hold the integer value for number input from the user

//sum = it will hold the integer value for sum of digits

//it will hold the integer value for

//taking input number from the user

cout<<"Enter a number: ";

//scanning the input number from the user

cin>>n;

//calculating the sum of the number

//of digits of the given number

while(n>0)

{

m=n%10;

sum=sum+m;

n=n/10;

}

//printing the sum of digits of given input

cout<<"Sum is= "<<sum<<endl;

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

n = it will hold the integer value of the input.
sum = it will hold the integer value for sum.
m = it will hold the integer value.

Input number from the user.

Program Logic Code.

Printing output for sum the digits.

C++ Program to Find ASCII Value of a Character

In this tutorial, we will learn to create a C++ program that will find the ASCII Value of a Character in C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ Programming.

Program to Find ASCII Value of a Character:-

American Standard Code For Information Interchange stands for ASCII. The ASCII is an encoded format. In c++ programming, we can take the input from the user in character format. In today’s program, we will take input in character format. Secondly, we will find the ASCII Value of a Character the input with the help of a small program. The ASCII values are the most useful code in any programing language to know the characters.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input character form the user for the program to find the ascii value.

3. Finding the ascii walue for the character input.

4. Printing the American Standard Code For Information Interchange value for the user.

5. End program.

1. Declaring the variables for the program.

2. Taking the input character form the user for the program to find the ascii value.

3. Finding the ascii walue for the character input.

4. Printing the American Standard Code For Information Interchange value for the user.

5. End program.

Program:-

/* C++ Program to Find ASCII Value of a Character */
#include <iostream>
using namespace std;

int main()
{   
    
    /*
    declaring the variables required for
    the program in character format type
    */
     char c;
    /*
    taking the input charcter value 
    form user for the program.
    */
     cout << "Enter a character: ";
    /*
    taking the input character value for the program.
    */
     cin >> c;
    /*
    Printing the American Standard Code For Information Interchange
    ASCII value for the input character.
    */
     cout << "ASCII Value of " << c << " is " << int(c);
    return 0;
}

/* C++ Program to Find ASCII Value of a Character */

#include <iostream>

using namespace std;

int main()

{

declaring the variables required for

the program in character format type

char c;

taking the input charcter value

form user for the program.

cout << "Enter a character: ";

taking the input character value for the program.

cin >> c;

Printing the American Standard Code For Information Interchange

ASCII value for the input character.

cout << "ASCII Value of " << c << " is " << int(c);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

c = it will hold the integer value of the Remainder.

Taking Input divisor and dividend from the user.

Calculating the quotient and the remainder.

Printing the output.

C++ Programs to Find Cube Root of Number

In this tutorial, we will learn to create a C++ program that will find Cube Root of given number using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators.
Basic input/output.
In-built functions.
mathematical functions.

What Is cube root?

Cube root , is a factor that we multiply by itself three times to get that number (2*2*2=8).A number which produces a number when cubed.

C++ Programs to Find Cube Root of Number.

Firstly we declare required header file and variable and also initiates required values in variable. Here in this program we are going find cube root of a given number first of all we take a value from user and pass this value to in-built function to find cube root of a number.

#include <bits/stdc++.h>
using namespace std;
int main()
{
  int num; //declaring variables
  cout <<"Enter any number : "; 
  cin >>num; // taking values from user.
  cout <<"Cube root of "<<num<<" is: "<<cbrt(num); // finding cuberoot.
  return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main()

{

int num; //declaring variables

cout <<"Enter any number : ";

cin >>num; // taking values from user.

cout <<"Cube root of "<<num<<" is: "<<cbrt(num); // finding cuberoot.

return 0;

}

Output

C++ Programs to Find Cube Root of Number

Function cbrt() takes only single parameter(num) and returns the cube root.which we hold in cube_root variable.

In the above program, we have first declared and initialized a set variables required in the program.

num = it will hold given number.

with the help of cbrt() in-built function we can find the cube of given number of user.

Step by step explanation of this program.

1:First we declare variable num.
2 :Then take a value from user and assign to num.

3 : Pass no variable to cube_root function (cbrt(num)).
4 : This function returns value to cube root .
5 : Print the value of cube_root.

Explanation of Cube root, cube root of a number is a value ,when multiplied by itself 3 times . For example, the cube root of 27, denoted as ³√27, is 3, because when we multiply 3 by itself thrice times we get 3 x 3 x 3 = 27 = 3³.

C++ Programs to Find Square Root of Number

In this tutorial, we will learn to create a C++ program that will find Square Root of given number using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators.
Basic input/output.
In-built functions.
mathematical functions.

What Is Square root?

Squares is found when numbers multiplying by itself Twice 5 * 5= 25. Where a square root of a number on getting multiplied by itself gives the original √25 = 5.
A square root of a number a is a number b such that b² =a.

C++ Programs to Find Square Root of Number.

Firstly we declare required header file and variable and also initiates required values in variable. Here in this program we are going find Square root of a given number first of all we take a value from user and pass this value to in-built function to find Square root of a number.

#include<iostream>
#include<math.h>
 using namespace std;
 int main()
{
float num; // declaring variable
cout<<"Enter any number:";
cin>>num; // taking value
cout<<"Square root of "<<num<<" is "<<sqrt(num); // finding squreroot
return 0;
}

#include<iostream>

#include<math.h>

using namespace std;

int main()

{

float num; // declaring variable

cout<<"Enter any number:";

cin>>num; // taking value

cout<<"Square root of "<<num<<" is "<<sqrt(num); // finding squreroot

return 0;

}

Output

C++ Programs to Find Square Root of Number

Function sqrt() takes a single argument(num) and returns the square root.

In the above program, we have first declared and initialized a set variables required in the program.

num = it will hold given number.

with the help of sqrt() in-built function we can find the square root of given number of user.

Step by step explanation of this program.

1:First we declare variable num.
2 :Then take a value from user and assign to num.

3 : Pass no variable to sqrt_root function (sqrt(num)).
4 : This function will find the square of given number .
5 : Print the value of sqrt(num).

Explanation of Square root.

So square root of a number is getting by multiplied itself gives the original as we can see in here √36 =6 .
so square root of 36 is 6. square root are written always in radical symbol (√).

C++ Program to Display Factors of a Number

In this tutorial, we will learn to create a C++ program that will find Factors of a number using C++ programming.

Prerequisites.

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators.
If else statement.
For Loop.
Basic input/output.
Basic c++ Programming.

What Is Factor of number is?

Factors of a number are numbers that divide the number completely and remainder of that number(Divisor) is equal to zero .

Example:->

The number 6 has four factors: 1, 2, 3, and 6 because all this number divide the number six completely.

C++ Program to Display Factors of a Number

In this program we find factor of given number using if -else statement and for loop. First we would declared and initialized the required variables. Next, we would prompt user to input the number . Later we will find factors of a given number.

#include <iostream>
using namespace std;

int main() 
{
    int num, i; //declaring variables 
    cout<<"Enter any  positive integer :"; // taking a postive number
    cin>>num;
    cout<<"Factors of gievn number "<<num <<" are ";
    for (i = 1; i <= num; ++i)  // iteration of loop till given number
   {
        if (num % i == 0) // finding factors
       {
            cout<<i <<" "; // printing factors.
        }
    }
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

int num, i; //declaring variables

cout<<"Enter any positive integer :"; // taking a postive number

cin>>num;

cout<<"Factors of gievn number "<<num <<" are ";

for (i = 1; i <= num; ++i) // iteration of loop till given number

{

if (num % i == 0) // finding factors

{

cout<<i <<" "; // printing factors.

}

return 0;

}

Output

C++ Program to Display Factors of a Number

In this program we will take a positive integer from user by prompting user

and with the help of loop and if else statement we will displays all the positive factors of that number.

In the above program, we have first declared and initialized a set variables required in the program.

num = It will hols number given by user.
= for iteration of loop and finding factor.

So finding the factors of a number we will run a loop from 1 to num, incrementing the loop value by 1 in each iteration.

The loop structure should look like this

Within the loop in each iteration we check the condition that i is a factor of num or not. To check factor we use divisibility of number by using modulo division.

i.e. if( num % i == 0) then i is a factor of num If i is a factor of num then we will print the value of i.So we will get the required factors of given number.

C++ Program to Multiply two Numbers

C++ Program to Multiply Two Numbers

In this tutorial, we will learn to create a C++ program that will Multiply Two Numbers in C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ Programming.

Program to Multiply Two Numbers:-

As we all know the integer, float, or double value in c++ programming. In c++ programming, we can take the input from the user in integer format. In today’s program, we will take input in number format. Secondly, we will Multiply the number with the help of a small program and the arithmetic operator “*”. The numbers are the most useful terminology in any programing language. For arithmetic manipulation in c++ programming, there are many predefined functions available.

Integers are the most use-full data types in any programming language. The integer values are used with operators to perform the best operations in C++ programming.

With the help of this program, we can take input and Multiply Two Numbers.

Algorithm to Multiply the numbers:-

1. Declaring the variables for the program.


2. Taking the input numbers from the user in number format.


3. Multiply the numbers and storing it in a variable.


4. End program.

1. Declaring the variables for the program.

2. Taking the input numbers from the user in number format.

3. Multiply the numbers and storing it in a variable.

4. End program.

Program to Multiply Two Numbers:-

/* C++ Program to Multiply Two Numbers */ 
#include <iostream>
using namespace std;

int main()
{
    //Declaring the variables for the program
    int fno, sno, multiply;
    
    //Taking input numbers from the user for multiplicaiton of the two values.
    cout << "Enter two numbers: ";
    cin >> fno >> sno;

    // sum of two numbers in stored in variable sum
    multiply = fno * sno;

    // Prints sum of two numbers 
    cout << fno << " * " <<  sno << " = " << multiply;     

    return 0;
}

/* C++ Program to Multiply Two Numbers */

#include <iostream>

using namespace std;

int main()

{

//Declaring the variables for the program

int fno, sno, multiply;

//Taking input numbers from the user for multiplicaiton of the two values.

cout << "Enter two numbers: ";

cin >> fno >> sno;

// sum of two numbers in stored in variable sum

multiply = fno * sno;

// Prints sum of two numbers

cout << fno << " * " << sno << " = " << multiply;

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

fno = it will hold the input number value from the user.
sno = it will hold the input number value from the user.
multiply = it will hold the sum value of the numbers.

Taking Input numbers from the user.

Calculating the multiply of two numbers.

Printing the output.