Category Archives: C++ Programs

c plus plus programs

C++ Program to Print Number Pattern

In this tutorial, we will learn to create a C++ program that will Print Number patterns using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
Basic arithmetic operations.
For loop in C++ Programming.

Print Number Pattern:-

The C++ language is a very powerful programming language. In C++ programming we can perform many operations with the help of codings. The C++ language is very easy to create any pattern. In this program, we will learn to Print Number Patterns with the help below code.

Algorithm:-

STEP 1: START

STEP 2: first declare the variables

STEP 3: Take input from number of rows from the user.

STEP 4: then start the parent for loop

STEP 5: now make the child for loop

STEP 6: in this child loop print the blank spaces

STEP 7: now use another child loop to start drawing<strong> Number Pattern</strong>

STEP 8: Now this for loop will also execute under the parent for loop

STEP 9: Print "\n" for changing the line before the increment of the main loop

STEP 10: increment of the main for loop

STEP 11: return the zero value for main function

STEP 1: START

STEP 2: first declare the variables

STEP 3: Take input from number of rows from the user.

STEP 4: then start the parent for loop

STEP 5: now make the child for loop

STEP 6: in this child loop print the blank spaces

STEP 7: now use another child loop to start drawing<strong> Number Pattern</strong>

STEP 8: Now this for loop will also execute under the parent for loop

STEP 9: Print "\n" for changing the line before the increment of the main loop

STEP 10: increment of the main for loop

STEP 11: return the zero value for main function

Program:-

To Print Number Pattern.

#include <iostream>
using namespace std;

int main()
{ 
    //declare the variables for the program
    int rw,i,j;
    //rw it will hold the integer value for the number of rows
    //i it will hold the integer value for the Parent for loop
    //i it will hold the integer value for the child for loop
    
    //taking input from the user number of rows for the pattern
    cout << "Enter number of rows: ";
    cin >> rw;
    
    //Making the pattern from the nested for loop
    for(i = 1; i <= rw; ++i)
    {
        for(j = 1; j <= i; ++j)
        {
            //printing the pattern on the output
            cout << j << " ";
        }
        cout << "\n";
    }
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

//declare the variables for the program

int rw,i,j;

//rw it will hold the integer value for the number of rows

//i it will hold the integer value for the Parent for loop

//i it will hold the integer value for the child for loop

//taking input from the user number of rows for the pattern

cout << "Enter number of rows: ";

cin >> rw;

//Making the pattern from the nested for loop

for(i = 1; i <= rw; ++i)

{

for(j = 1; j <= i; ++j)

{

//printing the pattern on the output

cout << j << " ";

}

cout << "\n";

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

i = it will hold the integer value to control parent for loop.
j = it will hold the integer value to control child for loop.
rw = it will hold the integer value.

Taking the input rows from the users.

Code for the pattern of the number.

Printing the rows of patterns.

C++ Program to Print Triangle of Star

In this tutorial, we will learn to create a c++ program that will create a Triangle of Stars using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics.

if-else Statements.
Looping statement.
Basic input/output.
Operators.

Triangle of Star

To print Triangle Star patterns in C++ , we will use two nested loops. The outermost loop is responsible for the number of rows in star (*) pyramid triangle,whereas inner one loop will print the required number of stars * in each row.

C++ Program to Creating a Triangle of Star.

In this program we will print Triangle of Star using nested for loop. We would first declared and initialized the required variables. Then we will create the Triangle of Star using below program.

#include <iostream>
using namespace std;

int main()
{
    int i,j; // declaring varibales
   
    for(i = 1; i <= 5; ++i) // printing pyramid
    {
        for(j = 1; j <= i; ++j)
        {
            cout << "* ";
        }
        cout << "\n";
    }
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

int i,j; // declaring varibales

for(i = 1; i <= 5; ++i) // printing pyramid

{

for(j = 1; j <= i; ++j)

{

cout << "* ";

}

cout << "\n";

}

return 0;

}

Output

C++ Program to Print Triangle of Star

In the above program, we have first declared and initialized a set variables required in the program.

i & j= for iteration.

In above program first we declare variables i and j, here we use 2 for loops.The outer loop will run for number of rows or pyramid and the inner loop print the number of stars to be displayed in each row.This is displayed using the following code.

And the final output of our program is like that.

C++ Program to check number positive or negative

In this tutorial,you will learn to create a C++ Program to check whether a number is positive or negative using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Basic input/output.
Operators.
looping statements.
Basic input/output.
Basic C++ programming.

What is Positive and Negative Number.

A Number which is greater than zero it is a positive number (Number>0).
And a Number which is less than zero it is negative number (Number<0).
Or A number which is equivalent to zero it is Not positive nor negative number (Number==0).

C++ Program to check whether a number is positive or negative

In this program we will find whether a number is positive, negative or zero series using if else statement. We would first declared and initialized the required variables. Next, we would prompt user to input any number. Later we will find that number is positive,negative or zero.

#include <iostream>
using namespace std;

int main()
{
    int num; // declaring variabled
	cout << " Input a number : ";   // taking value from user..
        cin >> num;
    if(num > 0) // positive condtion
    {
        cout << " The entered number is positive.";
    }
    else if(num < 0)  //negative condition
    {
        cout << " The entered number is negative.";
    }
    else
    {
        cout << " The number is zero.";
    }
    return 0;
}

#include <iostream>

using namespace std;

int main()

{

int num; // declaring variabled

cout << " Input a number : "; // taking value from user..

cin >> num;

if(num > 0) // positive condtion

{

cout << " The entered number is positive.";

}

else if(num < 0) //negative condition

{

cout << " The entered number is negative.";

}

else

{

cout << " The number is zero.";

}

return 0;

}

Output

Positive Value.

C++ Program to check number positive or negative

Negative Value.

Zero Value.

In the above program, we have first declared and initialized a set variables required in the program.

num = it will hold the value of number.

In the next statement user will be prompt to enter any number terms which will be assigned to variable ‘num’.

For finding given integer is positive ,negative or zero we will use We will use nested if else statement.

in above image within the if condition we check if(num > 0), number is greater than zero then number is Positive.

if the given number is less then Zero else if(num < 0) then number is negative.

else the number is zero.

In this program we find that a number is positive, negative or zero.The above approach is easiest way find the problem. First we check condition for positive number, then for negative or and later we find for zero.

C++ Program to Check Leap Year

In this tutorial, we will learn to create a c++ program that will find the given year is Leap year of not using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

C++ Operators
Conditional statement.
Basic input output .

What is Leap Year?

Example:

So logic behind to check whether a year is leap or not is:
Logic of Leap Year:
If the given value is completely divisible by 4, 100 and 400 then it is a leap year.
If the given value is divisible by 4 but not by 100 then it is a leap year.

Logic for not a Leap Year:
If the given value is not divisible by 4 then it is not a leap year
If the given value is divisible by 4 and 100 but not divisible by 400 then it is not a leap year.

For example,

1221 is not a leap year.
2000 is a leap year.
1890 is not a leap year.

Program to Check given year is a Leap Year or not.

Here fist we take a year from user and with help of logical operator(&& and ,|| or) we will check multiple condition in a single if statement and get the required result.

#include <iostream>
using namespace std;

int main() {
   int year;
   cout<<"enter any year :";
   cin>>year; //taking value from user..
   
   if (year % 4 == 0 && year % 100!= 0 || year%400 == 0) //logic
   {
     cout<<"is a leap year "<<year;
   }
   else
   {
      cout<<"is not a leap year " <<year;
   }
   return(0);
}

#include <iostream>

using namespace std;

int main() {

int year;

cout<<"enter any year :";

cin>>year; //taking value from user..

if (year % 4 == 0 && year % 100!= 0 || year%400 == 0) //logic

{

cout<<"is a leap year "<<year;

}

else

{

cout<<"is not a leap year " <<year;

}

return(0);

}

Output

C++ Program to Check Leap Year

In our program, we have first declared and initialized a set variables required in the program.

year =taking year value from user.

First of all take a value from user to check whether a year is leap or not is,

then we check if the given value is completely divisible by 4, 100 and 400 then it is a leap year.

If the given value is divisible by 4 but not by 100 then it is a leap year. As shown in above .So this the logic behind of finding given year is a leap year or not.

C++ Program to Find Perfect Number

In this tutorial, we will learn to create a c++ program that will find what is A Prefect Number using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

- Operators.
- Looping statements.
- C++ While Loop.
- Basic input/output.

What Is Perfect Number?

Perfect number is a positive integer number,that equals to sum of its positive divisors not include the number itself is equal to that number.

Example

Divisor of 28 are 1 + 2 + 4 + 7 + 14. and sum of these are (1+2+4+7+14=28). So we can say that 28 is a perfect number in which we will not induced 28 i.e exclude 28 .So number is called perfect when divisor of number added and that create the number itself called Perfect number.

C++ Program to Find Perfect Number.

So here we are going to create a program in which we take a value from user and we will find the given number is perfect or not? By method using adding all divisors of a number.

#include <iostream> 
using namespace std; 

int main()
{
    int num,i=1,sum=0; // declaring variables
    cout << "Enter a number: ";
    cin >> num;
      
   while(i<num)   // checking condition for perfect number
   {
       if(num%i==0)
       sum=sum+i;
       i++; 
   }
 if(sum==num)
    cout << num << " is a perfect number\n"; 
 else
    cout << num << " is not a perfect number\n";
 
return 0;
}

#include <iostream>

using namespace std;

int main()

{

int num,i=1,sum=0; // declaring variables

cout << "Enter a number: ";

cin >> num;

while(i<num) // checking condition for perfect number

{

if(num%i==0)

sum=sum+i;

i++;

}

if(sum==num)

cout << num << " is a perfect number\n";

else

cout << num << " is not a perfect number\n";

return 0;

}

Output

C++ Program to Find Perfect Number

In the above program, we have first declared and initialized a set variables required in the program.

num = holding given number
sum= adding all divisor.
i = for iteration of a loop.

Explanation of program, First we take the integer value in ‘num’ variable. So the condition is that A Perfect number is a number which is equal to sum of its divisor.

Example, 6’s divisor are 1, 2 and 3. and there sum is (1+2+3=6) ,the divisors of 6. So the number 6 is called as perfect number.

From the above image of a perfect number in sum,Suppose user entered value is: no = 6
Step by step explanation for loop is here.

In 1st Iteration…
Number is num= 6, sum = 0 and loop start at i = 1.
If (no % i == 0) // if( 6%1== 0 ) true.
here number is complete divisible So,
sum = sum + i // sum= 0 + 1 =1.

Now,Second Iteration..
Values of sum and i has altered as sum = 1 and i = 2.

If (no % i == 0) // if( 6 %2 ==0 ) true.
sum = sum + i // sum = 1 + 2 = 3.

Third Iteration.
Again the values of both sum and i has altered as sum = 3 and i = 3

If (6 % 3 == 0) // if( 6%3==0) true.
sum = sum + i //sum = 3 + 3 = 6.

Next fourth and fifth iterations ,condition inside the if will fail
6 % 4 == 0 (FALSE)
6 % 5 == 0 (FALSE)

In next iteration, the value of i becomes 6, So (6 < 6) false . So, the compiler will terminate the for loop.
Then, we check whether the value of sum is exactly equal to the no or Not.

If it is TRUE, the below cout<<” is a perfect number” statement will execute. else cout<<” is not a perfect number” statement will execute.

C++ Program to Display Armstrong Number Between Two Numbers

In this tutorial, we will learn to create a C++ program that will Display Armstrong Number Between Two Numbers in C++ programming.

Prerequisites.

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
While loop in C++ programming.

Program to Display Armstrong Number Between Two Numbers:-

In today’s tutorial, we will create a program that will find the Armstrong numbers between the given number range. First will take the number frame from the user and then will find the Armstrong Number.

With the help of this program, we can Display Armstrong Number Between Two Numbers.

Algorithm:-

1. Declare the variables for the program.

2. Taking the input numbers from and to by the user.

3. Calculating the <strong>Armstrong Numbers</strong>.  

4. Print the Result.

5. End the program.

1. Declare the variables for the program.

2. Taking the input numbers from and to by the user.

3. Calculating the <strong>Armstrong Numbers</strong>.

4. Print the Result.

5. End the program.

Program to Display Armstrong Number Between Two Numbers:-

#include <iostream>
using namespace std;

int main()
{
  //Decalring the variables for the program
  int num1, num2, i, num, digit, sum;
  
  //Taking input number first for the starting range
  cout << "Enter first number: ";
  cin >> num1;
  //Taking input number second for the ending range
  cout << "Enter second number: ";
  cin >> num2;

  //Finfing the Armstrong numbers in the input range
  cout << "Armstrong numbers between " << num1 << " and " << num2 << " are: " << endl;
  for(i = num1; i <= num2; i++)
  {
        sum = 0;
        num = i;

        for(; num > 0; num /= 10)
        {
            digit = num % 10;
            sum = sum + digit * digit * digit;
        }

        if(sum == i)
        {
            //printing the Armstrong numbers
            cout << i << endl;
        }
  }

  return 0;
}

#include <iostream>

using namespace std;

int main()

{

//Decalring the variables for the program

int num1, num2, i, num, digit, sum;

//Taking input number first for the starting range

cout << "Enter first number: ";

cin >> num1;

//Taking input number second for the ending range

cout << "Enter second number: ";

cin >> num2;

//Finfing the Armstrong numbers in the input range

cout << "Armstrong numbers between " << num1 << " and " << num2 << " are: " << endl;

for(i = num1; i <= num2; i++)

{

sum = 0;

num = i;

for(; num > 0; num /= 10)

{

digit = num % 10;

sum = sum + digit * digit * digit;

}

if(sum == i)

{

//printing the Armstrong numbers

cout << i << endl;

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

num1 = it will hold the integer value.
num2 = it will hold the integer value.
flag = it will hold the integer value.
digit = it will hold the integer value.
num = it will hold the integer value.
sum = it will hold the integer value.
i = it will hold the integer value.

Taking the input integer number interval from the user.

Calculating the Armstrong numbers.

Printing the output numbers.

C++ Program to Check Armstrong Number

In this tutorial, we will learn to create a C++ program that will Check Armstrong Number in C++ programming.

Prerequisites.

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
While loop in C++ programming.

Program to Check Armstrong Number:–

In today’s tutorial, we will create a program that will find the Armstrong numbers from the given number. First will take the number from the user and then will find the Armstrong Number.

With the help of this program, we can Check Armstrong Number.

Algorithm:-

1. Declare the variables for the program.

2. Taking the input numbers from the user.

3. Checking the Armstrong Numbers.  

4. Print the Result.

5. End the program.

1. Declare the variables for the program.

2. Taking the input numbers from the user.

3. Checking the Armstrong Numbers.

4. Print the Result.

5. End the program.

Program to Check Armstrong Number:-

/* C++ Program to Check Armstrong Number */
#include <iostream>
using namespace std;

int main() 
{
    //declaring the variables for the program
    int num, ognum, rmdr, result = 0;
    //taking input number from the user to check the Armstrong number 
    cout << "Enter a 3-digit integer: ";
    //Scanning the input number given by the user in program
    cin >> num;
    ognum = num;
    //checking number if its a arm strong number or not
    while (ognum != 0) {
        // remainder contains the last digit
        rmdr = ognum % 10;
        
        result += rmdr * rmdr * rmdr;
        
        // removing last digit from the orignal number
        ognum /= 10;
    }

    if (result == num)
        //printing the number is an arm strong number
        cout << num << " is an Armstrong number.";
    else
        //printing the number is not an arm strong number
        cout << num << " is not an Armstrong number.";

    return 0;
}

/* C++ Program to Check Armstrong Number */

#include <iostream>

using namespace std;

int main()

{

//declaring the variables for the program

int num, ognum, rmdr, result = 0;

//taking input number from the user to check the Armstrong number

cout << "Enter a 3-digit integer: ";

//Scanning the input number given by the user in program

cin >> num;

ognum = num;

//checking number if its a arm strong number or not

while (ognum != 0) {

// remainder contains the last digit

rmdr = ognum % 10;

result += rmdr * rmdr * rmdr;

// removing last digit from the orignal number

ognum /= 10;

}

if (result == num)

//printing the number is an arm strong number

cout << num << " is an Armstrong number.";

else

//printing the number is not an arm strong number

cout << num << " is not an Armstrong number.";

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

ognum = it will hold the integer value.
rmdr = it will hold the integer value.
result = it will hold the integer value.
num = it will hold the integer value.

Taking the input integer number from the user.

Checking the Armstrong numbers.

Printing the output.

C++ Program to Display Prime Numbers Between Two Numbers

In this tutorial, we will learn to create a C++ program that will check that provided number is Prime or Not using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators.
Basic input/output.
Basic C++ Programming.
If else statement.
Looping statements.

What Is Prime number?

Any positive integer number which is greater than 1 (Num > 1 ) and only it can be divisible by itself and by 1 and it has max two factors is called as prime number.Rather we can say that a prime number is a number which only divided by himself or 1.

Example:->

Note: 2 is the only positive(even) and smallest Prime number.

primeno

In our program we will find Prime numbers between two numbers using for loop.

C++ Program to Display Prime Numbers Between Two Numbers

Firstly we declare required header file and variable and also initiates required values in variable. Next we take value from user at run time and then after we will find that the given value is prime number or not.Let’s take a look to the program.

#include <bits/stdc++.h>
using namespace std;

int main()
{
	// Declaring the variables
	int l, u, i, j, count;


	// taking values form user.
	cout << "Enter lower and upper interval: ";
	cin >> l>>u; 
	
	//  displaying prime number.
	cout << "\nPrime numbers between "
		<< l << " and " << u << " are: ";

	// Traversing each number in the interval
	for (i = l; i <= u; i++) 
	{		// Skiping 0 and 1 they are not prime numbers
		if (i == 1 || i == 0)
		continue;
	count = 1;
		for (j = 2; j <= i / 2; ++j) {
			if (i % j == 0) {
				count = 0;
				break;
			}
		}
		//if count = 1 means i is prime.
		// and count = 0 means i is not prime.
		if (count == 1)
			cout << i << " ";
	}
	return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main()

{

// Declaring the variables

int l, u, i, j, count;

// taking values form user.

cout << "Enter lower and upper interval: ";

cin >> l>>u;

// displaying prime number.

cout << "\nPrime numbers between "

<< l << " and " << u << " are: ";

// Traversing each number in the interval

for (i = l; i <= u; i++)

{ // Skiping 0 and 1 they are not prime numbers

if (i == 1 || i == 0)

continue;

count = 1;

for (j = 2; j <= i / 2; ++j) {

if (i % j == 0) {

count = 0;

break;

}

//if count = 1 means i is prime.

// and count = 0 means i is not prime.

if (count == 1)

cout << i << " ";

}

return 0;

}

Output

C++ Program to Display Prime Numbers Between Two Numbers

In the above program, we have first declared and initialized a set variables required in the program.

l = it will hold lower value.
u=it will hold upper limit.
i and j= for iteration.
count = count will print prime numbers is count=1.

In the next statement user will enter two number which will be assigned in variables ‘l’ and ‘u’.

lower and upper limit of loop Now loop start from l to given number(u).In ever iteration we will check the numbers between the interval l and u . For each number with in the for loop, will be checked if this number is prime value of count =1 if not the value of count remain zero(0).

If count=1 it is a prime then print the number.

Then the next number in the loop is checked, till all numbers between l and u are checked.

And finally we print all the number between given numbers.

C++ Program to Check Whether a Number is Prime or Not

In this tutorial, we will learn to create a C++ program that will Check Whether a Number is Prime or Not using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
For loop in C++ programming.
Conditional Statements in C++ programming.
Arithmetic operations in C++ Programming.

Program to Check Whether a Number is Prime or Not:-

In c++ programming, it is possible to take numerical input from the user and check if that number is Prime Number or not. The prime number means a number that is only divisible by itself.

With the help of this program, we can Check Whether a Number is Prime or Not.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a prime number or not.

4. Printing the result.

5. End the program.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a prime number or not.

4. Printing the result.

5. End the program.

Program to Check Whether a Number is Prime or Not:-

#include <iostream>
using namespace std;

bool checkPrimeNumber(int);

int main() 
{
    //declaring the variables for the program
    int n;
  
    //taking the input from the user 
    cout << "Enter a positive  integer: ";
    cin >> n;
   
    //Printing the number is prime or not 
    if (checkPrimeNumber(n))
        cout << n << " is a prime number.";
    else
        cout << n << " is not a prime number.";
    return 0;
}

bool checkPrimeNumber(int n) 
{
    //checking the [prime number]
    bool isPrime = true;

    // 0 and 1 are not prime numbers
    if (n == 0 || n == 1) {
        isPrime = false;
    }
    else {
        for (int i = 2; i <= n / 2; ++i) {
            if (n % i == 0) {
                isPrime = false;
                break;
            }
        }
    }
    return isPrime;
}

#include <iostream>

using namespace std;

bool checkPrimeNumber(int);

int main()

{

//declaring the variables for the program

int n;

//taking the input from the user

cout << "Enter a positive integer: ";

cin >> n;

//Printing the number is prime or not

if (checkPrimeNumber(n))

cout << n << " is a prime number.";

else

cout << n << " is not a prime number.";

return 0;

}

bool checkPrimeNumber(int n)

{

//checking the [prime number]

bool isPrime = true;

// 0 and 1 are not prime numbers

if (n == 0 || n == 1) {

isPrime = false;

}

else {

for (int i = 2; i <= n / 2; ++i) {

if (n % i == 0) {

isPrime = false;

break;

}

return isPrime;

}

Output:-

In the above program, we have first initialized the required variable.

no= it will hold the integer value of the input.
i = it will hold the integer value.
flag = it will hold the integer value.

Input message for the user for the integer value.

Program Logic Code.

Printing output prime number or not.

C++ Program to Check character is Vowel or Consonant

In this tutorial, we will learn to create a C++ Program to Check character is Vowel or Consonant. In this example we will check whether the entered character by the user is a vowel or a consonant using C++ programming.

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators
Condition statement.
logical operator.
Basic input/output.
Basic C++ programming.

What Is Vowel and consonant?

Vowel :=> Sound that allowing breath to flow out of mouth, without closing any part of the mouth is called as vowel.
Consonant:=> Sound made by blocking air from flowing out of the mouth with the teeth or throat is called as Consonant.

Example

As we know A E I O U are called vowels. And renaming alphabets except these 5 vowels are called consonants.

Program to Check the given value is Vowel or consonant.

So here we creating a program in which we will find the given character is vowel or consonant.
As we know a,e,i,o,u are only vowel and rest are consonant.So simply we will check these and if given character belongs to them then it is a vowel and if not its consonant simple isn’t it .let’s have a look at program.

#include <bits/stdc++.h>
using namespace std;
int main()
{
    char ch;
    cout<<"enter any characetr :";
    cin>>ch; //taking value from user.
       // checking condition for upper and lower case both.....
  if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' &&ch <= 'Z')) {
    if (ch=='a' || ch=='A' || ch=='e' || ch=='E' || ch=='i' || ch=='I' || ch=='o' || ch=='O' || ch== 'u' || ch=='U')
      cout<<ch<<" is a vowel ";
    else
      cout<<ch<<" is a consonant ";
  }
  else    // checking if value given is not character...
 {
    cout<<ch<<"is neither a vowel nor a consonant ";
 }

  return 0;
}

#include <bits/stdc++.h>

using namespace std;

int main()

{

char ch;

cout<<"enter any characetr :";

cin>>ch; //taking value from user.

// checking condition for upper and lower case both.....

if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' &&ch <= 'Z')) {

if (ch=='a' || ch=='A' || ch=='e' || ch=='E' || ch=='i' || ch=='I' || ch=='o' || ch=='O' || ch== 'u' || ch=='U')

cout<<ch<<" is a vowel ";

else

cout<<ch<<" is a consonant ";

}

else // checking if value given is not character...

{

cout<<ch<<"is neither a vowel nor a consonant ";

}

return 0;

}

Output

C++ Program to Check character is Vowel or Consonant.

Note: Here we assumes that the user will enter an alphabet. If not so then non-alphabetic character, it displays the character is neither a vowel nor a consonant.

In the above program, we have first declared a variables required in the program.

ch= hold given character.

First of all user prompted to enter any character which will be assign in ch variable.

Then with the help of if-else statement we will check the inputted character is a vowel or consonant, using following logic

As user inputs any character we will check whether it’s a vowel both in lower-case and upper-case condition we check if belongs to in vowel or consonant. if it is vowel we will show following message.

If a character doesn’t belong to this condition then it is consonant ,

and if doesn’t meet any of them vowel and consonant it might be a digit or a special symbol.

So in this tutorial we have learn to find given character is vowel or consonant.

C++ Programs to Check Palindrome String

In this tutorial, we will learn to create a c++ program that checks Palindrome String using c++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C ++ programming topics:

Operators.
Basic input/output.
String
mathematical functions.
in-built functions.

What Is Palindrome of String?

A palindrome of a String that reads the same backward and forward.

Example : dad , nayan , pop, abcba and etc…

C++ Programs to Check Palindrome String.

#include<iostream>
#include<string.h>
using namespace std;
int main()
{
        char strng[100];
        int i, len ,cmp = 0;    // declaring variables.

        cout<<"\n Enter a String : ";
        cin>>strng;     // taking string from user.

        len = strlen(strng);    // finding the length of string.

        for(i=0;i < len ;i++) // iterate to till length. 
        {
                if(strng[i] != strng[len-i-1])  // comparing string 
                {
                        cmp = 1;
                        break;
                }
        }    
        if(cmp) // condition for cmp=1.
        {
                cout<<" "<<strng<<" is not a palindrome"<<endl;
        }    
        else   // condition  for cmp=0.
        {
                cout<<" "<<strng<< " is a palindrome"<<endl;
        }
        return 0;
}

#include<iostream>

#include<string.h>

using namespace std;

int main()

{

char strng[100];

int i, len ,cmp = 0; // declaring variables.

cout<<"\n Enter a String : ";

cin>>strng; // taking string from user.

len = strlen(strng); // finding the length of string.

for(i=0;i < len ;i++) // iterate to till length.

{

if(strng[i] != strng[len-i-1]) // comparing string

{

cmp = 1;

break;

}

if(cmp) // condition for cmp=1.

{

cout<<" "<<strng<<" is not a palindrome"<<endl;

}

else // condition for cmp=0.

{

cout<<" "<<strng<< " is a palindrome"<<endl;

}

return 0;

}

Output

Palindrome string.

C++ Programs to Check Palindrome String

Not a Palindrome string.

In the above program, we have first declared and initialized a set variables required in the program.

strng =it will hold given string.
i= for iteration.
cmp= for holding true false value.
len = it will hold length of string.

In the next statement user will be prompted to enter a string which will be assigned to variable ‘strng’.

after that with the help of strlen() function we find the length of string.

Now for loop iterator upto ‘len’ number of terms. Inside the loop we compare string.

First character in the strng is the same as last character in the same string.
is the first character is the same as ‘len-i-1’th character and so on .This process continues till length of a string .

If any above condition fails, the cmp varibale is set to cmp=1 which is true(1), which implies that the string is not a palindrome.

If above condition satisfied, the cmp variable is all ready set to cmp=0 which is false(0), which implies that the string is a palindrome.

C++ Programs to Check Given Number is Palindrome or not

In this tutorial, we will learn to create a C++ program that will Check Given Number is Palindrome or not using C++ programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C++ programming topics:

Operators in C++ Programming.
Basic Input and Output function in C++ Programming.
Basic C++ programming.
For loop in C++ programming.
Conditional Statements in C++ programming.
Arithmetic operations in C++ Programming.

What is a palindrome number?

The Palindrome number means a number that is the same when we read it from forward and reverse.

For example:-

1221 this is a palindrome number is the same when we write it in reverse order 1221.
123 this is not a palindrome number it is not the same when we write it in reverse order 321.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a Palindrome number or not.

4. Printing the result.

5. End the program.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a Palindrome number or not.

4. Printing the result.

5. End the program.

Program to Check Whether a Number is Palindrome or Not:-

To check whether a number is a Palindrome Number or not. In today’s C++ program we will write code for checking. First, we will take a number in input and then pass it into the program to Check Whether a Number is Palindrome or Not.

With the help of the below program, we can Check Palindrome or Not.

Program Code:-

#include <iostream>
using namespace std;

int main()
{
    //Declaring the variables for the program.
     int n, num, digit, rev = 0;
    //Taking the input from user positive integer value
     cout << "Enter a positive number: ";
     cin >> num;
    
     n = num;
    //Checking the palindrome numbers
     do
     {
         digit = num % 10;
         rev = (rev * 10) + digit;
         num = num / 10;
     } while (num != 0);
    
    //Printing the output checked number is palindrome or not.
     cout << " The reverse of the number is: " << rev << endl;
     if (n == rev)
         cout << " The number is a palindrome.";
     else
         cout << " The number is not a palindrome.";

    return 0;
}

#include <iostream>

using namespace std;

int main()

{

//Declaring the variables for the program.

int n, num, digit, rev = 0;

//Taking the input from user positive integer value

cout << "Enter a positive number: ";

cin >> num;

n = num;

//Checking the palindrome numbers

{

digit = num % 10;

rev = (rev * 10) + digit;

num = num / 10;

} while (num != 0);

//Printing the output checked number is palindrome or not.

cout << " The reverse of the number is: " << rev << endl;

if (n == rev)

cout << " The number is a palindrome.";

else

cout << " The number is not a palindrome.";

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

num= it will hold the integer value of the input.
n = it will hold the integer value.
digit = it will hold the integer value.
rev = it will hold the integer value.

Input message for the user for the integer value.

Program Logic Code.

Printing output Palindrome number or not.