Category Archives: C Programs

C Programs

C Program to sort Word in String in Descending Order

In this tutorial, we will learn to create a C program that will sort Word in String in Descending Order using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in C Programming.
Conditional statement in C Programming.

Sort Word in String in Descending Order:-

As we all know String is a collection of similar data type elements. In an array, only one variable is declared which can store multiple values. First will take the string input from the user. Then will pass that string to the for loop to sort it in reverse order. And at last, we will sort Word in String in Descending Order C Programming Language.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the array size from the user.

3. Taking the elements of the array.

4. Sorting the elements of the array.

5. Printing the results.

6. End program.

1. Declaring the variables for the program.

2. Taking the array size from the user.

3. Taking the elements of the array.

4. Sorting the elements of the array.

5. Printing the results.

6. End program.

Program:-

sort Word in String in Descending Order

#include<stdio.h>
#include<string.h>
int main()
{
    //declaring the variable for the program 
    char str[100], flag;
    int i, j, len;
    
    //display the message to take the input from the user
    printf("Enter any string: ");
    //Scanning the string input from the user
    gets(str);
    
    //Calculating the length of array
    len = strlen(str);
    
    //Sorting the string into the reverse format 
    for(i=0; i<len; i++)
    {
        for(j=0; j<(len-1); j++)
        {
            if(str[j]<str[j+1])
            {
                flag = str[j];
                str[j] = str[j+1];
                str[j+1] = flag;
            }
        }
    }
    
    //Printing the output string in decending order
    printf("\nSame string in descending order:\n%s", str);
  
    return 0;
}

#include<stdio.h>

#include<string.h>

int main()

{

//declaring the variable for the program

char str[100], flag;

int i, j, len;

//display the message to take the input from the user

printf("Enter any string: ");

//Scanning the string input from the user

gets(str);

//Calculating the length of array

len = strlen(str);

//Sorting the string into the reverse format

for(i=0; i<len; i++)

{

for(j=0; j<(len-1); j++)

{

if(str[j]<str[j+1])

{

flag = str[j];

str[j] = str[j+1];

str[j+1] = flag;

}

//Printing the output string in decending order

printf("\nSame string in descending order:\n%s", str);

return 0;

}

Output:-

In the above program, we have first initialized the required variable

str[100] = it will hold the elements in a string.
flag = it will hold the number of elements in a string
len = it will hold the integer value for the length of the string.
i = it will hold the integer value to control the array.
j = it will hold the integer value to control the array.

Taking input string from the user.

Checking the length of string,

Sorting the string in reverse order.

Printing the results.

C Program to count Characters with and without Space

In this tutorial, you will learn about the C Program to count Characters with and without Space with a practical example.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
Concepts of while loop.
Conditional Statements in C programming.
Using file functions of c language.

Count Characters with and without Space

As we all know the String is a collection of character data types. In strings, only one variable is declared which can store multiple values. First will take the string from the user. Then will pass that string to a while loop for counting. The C programming language has many pre-defined functions for string manipulation. but in today’s tutorial, we will count Characters with and without Space.

With the help of this program, we can count Characters with and without Space

Algorithm:-

1. Declaring the variables for the program. 

2. Taking the input string from the user. 

3. Reading the string. 

4. Counting the Data in the string. 

5. Printing the results. 

6. End program.

1. Declaring the variables for the program.

2. Taking the input string from the user.

3. Reading the string.

4. Counting the Data in the string.

5. Printing the results.

6. End program.

Program:-

#include<stdio.h>

int main()
{
    //declaraiton of variables in program
    char str[100];
    int i, countWithSpace=0, countWithoutSpace=0;
    
    //Taking the input string from the user
    printf("Enter any string: ");
    //reading the string from the user
    gets(str);
    
    //reading characters from taken input string 
    for(i=0; str[i]!='\0'; i++)
    {
        countWithSpace++;
    }
    for(i=0; i<countWithSpace; i++)
    {
        if(str[i]==32)
            countWithoutSpace++;
    }
    
    //printing the number of characters with and without spaces.
    countWithoutSpace = countWithSpace-countWithoutSpace;
    printf("\nNumber of character (with space) = %d", countWithSpace);
    printf("\nNumber of character (without space) = %d", countWithoutSpace);
  
    return 0;
}

#include<stdio.h>

int main()

{

//declaraiton of variables in program

char str[100];

int i, countWithSpace=0, countWithoutSpace=0;

//Taking the input string from the user

printf("Enter any string: ");

//reading the string from the user

gets(str);

//reading characters from taken input string

for(i=0; str[i]!='\0'; i++)

{

countWithSpace++;

}

for(i=0; i<countWithSpace; i++)

{

if(str[i]==32)

countWithoutSpace++;

}

//printing the number of characters with and without spaces.

countWithoutSpace = countWithSpace-countWithoutSpace;

printf("\nNumber of character (with space) = %d", countWithSpace);

printf("\nNumber of character (without space) = %d", countWithoutSpace);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

str[100] = it will hold the string value.
i= it will hold the integer value of the loop.
countWithSpace = it will hold the integer value of the counting.
countWithoutSpace= it will hold the integer value of the counting.

Taking Input string from the user.

Counting the characters from the string entered by the user .

Printing output data characters.

C Program to Print Sum of Digit in given Number

In this tutorial, we will learn to create a C program that will Print Sum of digits in a given Number using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
While loop in C programming.
Conditional Statements in C programming.
Arithmetic operations in C Programming.

Program to Print Sum of digits in a given Number

In c programming, it is possible to take numerical input from the user and Print Sum of digits in a given number with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy.

With the help of this program, we can Print Sum of digits in a given number.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the digits numbers.

4. Calculating the sum of numbers.

5. Printing the result numbers.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the digits numbers.

4. Calculating the sum of numbers.

5. Printing the result numbers.

Program to Print Sum of digits in a given number:-

#include<stdio.h>

int main()
{
    //declaring the variable for the program 
    
    int no, evenSum=0, oddProd=1, rem, temp;
    //showing the message for the input 
    printf("Enter any number: ");
    //scanning the number
    scanf("%d", &no);
    
    //using while loop to sort even odd numbers and calculating
    //the sum nad products of digits of a number
    while(no>0)
    {
        rem = no%10;
        if(rem%2==0)
            evenSum = evenSum + rem;
        else
            oddProd = oddProd * rem;
        no = no/10;
    }
    
    //Printing the output of the program
    printf("\nSum of Even Digit = %d", evenSum);
    printf("\nProduct of Odd Digit = %d", oddProd);
 
    return 0;
}

#include<stdio.h>

int main()

{

//declaring the variable for the program

int no, evenSum=0, oddProd=1, rem, temp;

//showing the message for the input

printf("Enter any number: ");

//scanning the number

scanf("%d", &no);

//using while loop to sort even odd numbers and calculating

//the sum nad products of digits of a number

while(no>0)

{

rem = no%10;

if(rem%2==0)

evenSum = evenSum + rem;

else

oddProd = oddProd * rem;

no = no/10;

}

//Printing the output of the program

printf("\nSum of Even Digit = %d", evenSum);

printf("\nProduct of Odd Digit = %d", oddProd);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no = it will hold the integer value of the input.
sum = it will hold the integer value for sum.
m = it will hold the integer value.

Input number from the user.

Program Logic Code.

Printing output for sum the digits.

C Program to Print Next Successive Character

In this tutorial, we will learn to create a C program that will Print the Next Successive Character in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
Conditional statements in c programming.
String functions of c programming.

Program to Print Next Successive Character

As we all know the String is a collection of character data types. In strings, only one variable is declared which can store multiple values. First, we will take the input character from the user then we will Print the Next Successive Character. The ASCII value of the input character will be scanned and increased by 1 and print the character value.

With the help of this program, we can Print the Next Successive Character.

Algorithm:-

1. Declare the variables for the program. 

2. Take the input letter or character from the user. 

3. Find the ASCII value of that number. 

4. Addind that value by 1.

5. Printing the next character using the conditional statement. 

6. End the program.

1. Declare the variables for the program.

2. Take the input letter or character from the user.

3. Find the ASCII value of that number.

4. Addind that value by 1.

5. Printing the next character using the conditional statement.

6. End the program.

Program to Sort Word in String in Ascending Order:-

#include<stdio.h>

int main()
{
    //declaring the variables for the program
    char ch;
    
    //Taking the input character from the user 
    printf("Enter any character: ");
    //Scanning the input provided from the user
    scanf("%c", &ch);
    
    //printing the successor of that character
    printf("\n");
    if(ch>=65 && ch<90)
        printf("%c", ch+1);
    else if(ch>=97 && ch<122)
        printf("%c", ch+1);
    else if(ch==90)
        printf("%c", 65);
    else if(ch==122)
        printf("%c", 122);
    else
        printf("%c", ch);

    return 0;
}

#include<stdio.h>

int main()

{

//declaring the variables for the program

char ch;

//Taking the input character from the user

printf("Enter any character: ");

//Scanning the input provided from the user

scanf("%c", &ch);

//printing the successor of that character

printf("\n");

if(ch>=65 && ch<90)

printf("%c", ch+1);

else if(ch>=97 && ch<122)

printf("%c", ch+1);

else if(ch==90)

printf("%c", 65);

else if(ch==122)

printf("%c", 122);

else

printf("%c", ch);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

ch = it will hold the character value for the input.

Input character message and Scan the character from the user.

Getting the ASCII value and calculating the next letter using the conditional statement.

And printing the output character.

C Program to Print Number in Words

C Program to Print Number in Words.

In this tutorial, we will learn to create a C program that will Print Numbers in Words in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
While Loop in c programming.
Switch Case in

Print Numbers in Words

As we all know the c programming is a very powerful language. In the c programming language, we have many pre-defined functions for arithmetic operations. but today we will take the input number and Print Number in Words with the help of the c programming language.

With the help of this program, we can Print Numbers in Words.

Algorithm:-

1. Declare the variables for the program. 

2. Take the input number from the user.

3. Pass that number to a condition.

4. Print the output string after checking.

5. End the program.

1. Declare the variables for the program.

2. Take the input number from the user.

3. Pass that number to a condition.

4. Print the output string after checking.

5. End the program.

Program to Print Numbers in Words:-

/**
 * C program to print number in words
 */

#include <stdio.h>

int main()
{
    //declaring variables for the program
    int no, num = 0;

    /* Input number from user */
    printf("Enter any number to print in words: ");
    scanf("%d", &no);

    /* Store reverse of n in num */
    while(no != 0)
    {
        num = (num * 10) + (no % 10);
        no /= 10;
    }

    /* 
     * Extract last digit of number and print corresponding digit in words
     * till num becomes 0
     */
    while(num != 0)
    {
        switch(num % 10)
        {
            //printing the digits in words
            case 0: 
                printf("Zero ");
                break;
            case 1: 
                printf("One ");
                break;
            case 2: 
                printf("Two ");
                break;
            case 3: 
                printf("Three ");
                break;
            case 4: 
                printf("Four ");
                break;
            case 5: 
                printf("Five ");
                break;
            case 6: 
                printf("Six ");
                break;
            case 7: 
                printf("Seven ");
                break;
            case 8: 
                printf("Eight ");
                break;
            case 9: 
                printf("Nine ");
                break;
        }
        
        num = num / 10;
    }

    return 0;
}

/**

* C program to print number in words

#include <stdio.h>

int main()

{

//declaring variables for the program

int no, num = 0;

/* Input number from user */

printf("Enter any number to print in words: ");

scanf("%d", &no);

/* Store reverse of n in num */

while(no != 0)

{

num = (num * 10) + (no % 10);

no /= 10;

}

* Extract last digit of number and print corresponding digit in words

* till num becomes 0

while(num != 0)

{

switch(num % 10)

{

//printing the digits in words

case 0:

printf("Zero ");

break;

case 1:

printf("One ");

break;

case 2:

printf("Two ");

break;

case 3:

printf("Three ");

break;

case 4:

printf("Four ");

break;

case 5:

printf("Five ");

break;

case 6:

printf("Six ");

break;

case 7:

printf("Seven ");

break;

case 8:

printf("Eight ");

break;

case 9:

printf("Nine ");

break;

}

num = num / 10;

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no = it will hold the integer value of number input.
num = it will hold the integer value of number input.

Taking input number from the user.

Program logic.

Printing Output numbers.

C Program to Find LCM & HCF

In this tutorial, we will learn to create a C program that will Find LCM & HCF using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
While loop in C programming.
Arithmetic operations in C Programming.

Program to Find LCM & HCF

In c programming, it is possible to take numerical input from the user and Find LCM & HCF with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy.

With the help of this program, we can Find LCM & HCF.

Here,

LCM:-Least Common Multiple.

HCF:- Highest Common Factor.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the HCF.

4. Calculating the LCM.

5. Printing the result numbers.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the HCF.

4. Calculating the LCM.

5. Printing the result numbers.

Program to Find HCF and LCM:-

#include <stdio.h>
int main()
{
  //declaring the local variables for program
  int a, b, x, y, t, hcf, lcm;
  
  //taking two numbers from user as a input
  printf("Enter two integers\n");
  scanf("%d%d", &x, &y);
  
  //assigning the values
  a = x;
  b = y;
    //Finding HCF & LCM
    while (b != 0) {
        t = b;
        b = a % b;
        a = t;
      }


  hcf = a;
  lcm = (x*y)/hcf;
  
  //Printing output of the program
  printf("Highest common factor of %d and %d = %d\n", x, y, hcf);
  printf("Least common multiple of %d and %d = %d\n", x, y, lcm);


  return 0;
}

#include <stdio.h>

int main()

{

//declaring the local variables for program

int a, b, x, y, t, hcf, lcm;

//taking two numbers from user as a input

printf("Enter two integers\n");

scanf("%d%d", &x, &y);

//assigning the values

a = x;

b = y;

//Finding HCF & LCM

while (b != 0) {

t = b;

b = a % b;

a = t;

}

hcf = a;

lcm = (x*y)/hcf;

//Printing output of the program

printf("Highest common factor of %d and %d = %d\n", x, y, hcf);

printf("Least common multiple of %d and %d = %d\n", x, y, lcm);

return 0;

}

Output:-

In the above program we have first initialized the required variable.

x = it will hold the integer value1.
y = it will hold the integer value2.
a = it will hold the integer value of x.
b = it will hold the integer value of y.
t = it will hold the integer temporary value.
hcf = it will hold the integer value of calculated hcf.
lcm= it will hold the integer value of calculated lcm .

Input number from user.

Program Logic Code.

Printing output

C Program to Add n Numbers

In this tutorial, we will learn to create a C program that will Add n Numbers using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in C programming.
Arithmetic operations in C Programming.

Program to Add n Numbers

In c programming, it is possible to take numerical input from the user and Add n Numbers with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy. In C language, we can do many arithmetic operations.

With the help of this program, we can Add n Numbers.

Here,

We will first take the input

The second will make a series and add the numbers.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Passing that number to a for loop.

4. Adding the series to a variable.

5. Printing the result numbers.

6. End Program.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Passing that number to a for loop.

4. Adding the series to a variable.

5. Printing the result numbers.

6. End Program.

Program to Add n Numbers:-

#include <stdio.h>
int main() 
{
    //declaring the variables for the program.
    int no, i, sum = 0;

    //taking input from the user a positive number
    printf("Enter any positive integer value : ");
    
    //scanning the input from the user.
    scanf("%d", &no);

    //using the for loop for the calculating the sum of n numbers
    for (i = 1; i <= no; ++i) {
        sum += i;
    }
    
    //Printing the output Sum for the n nubers
    printf("Sum = %d", sum);
    return 0;
}

#include <stdio.h>

int main()

{

//declaring the variables for the program.

int no, i, sum = 0;

//taking input from the user a positive number

printf("Enter any positive integer value : ");

//scanning the input from the user.

scanf("%d", &no);

//using the for loop for the calculating the sum of n numbers

for (i = 1; i <= no; ++i) {

sum += i;

}

//Printing the output Sum for the n nubers

printf("Sum = %d", sum);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no = it will hold the integer value.
i = it will hold the integer value.
sum = it will hold the integer value.

Input number from the user.

Program Logic Code.

Printing output

C Program to Add Subtract Multiply Divide

In this tutorial, we will learn to create a C program that will Add, Subtract, Multiply & Divide using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
Arithmetic operations in C Programming.

Program to Add Subtract Multiply Divide

In c programming, it is possible to take numerical input from the user and Add, Subtract, Multiply & Divide with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy.

With the help of this program, we can Add Subtract Multiply Divide.

Here,

We will first take the input

The second will make a series and add the numbers.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input numbers from the user.

3. Passing those numbers to the arithmetic operations.

4. Add,substract,multiply,divide the numbers.

5. Printing the result number.

6. End Program.

1. Declaring the variables for the program.

2. Taking the input numbers from the user.

3. Passing those numbers to the arithmetic operations.

4. Add,substract,multiply,divide the numbers.

5. Printing the result number.

6. End Program.

Program to Add Subtract Multiply Divide:-

#include <stdio.h>
#include <stdlib.h>

int main()
{
    //declaring the variables for the program.
    int no1,no2;
    
    //taking the input numbers from the user
    printf("Enter the first number: ");
    scanf("%d",&no1);
    printf("Enter the second number: ");
    scanf("%d",&no2);
    
    //Printing the output addition for the numbers
    printf("\nAddition of %d + %d",no1,no2);
    printf(" = %d",(no1+no2 ));
    //Printing the output substraction for the numbers
    printf("\nSubstraction of %d - %d",no1,no2);
    printf(" = %d",(no1-no2));
    
    //Printing the output multipliccation for the numbers
    printf("\nMultiplication of %d X %d",no1,no2);
    printf(" = %d",(no1*no2 ));
    
    //Printing the output division for the numbers
    printf("\nDivision of  %d / %d",no1,no2);
    printf(" = %d",(no1/no2 ));
    
 
    return 0;
}

#include <stdio.h>

#include <stdlib.h>

int main()

{

//declaring the variables for the program.

int no1,no2;

//taking the input numbers from the user

printf("Enter the first number: ");

scanf("%d",&no1);

printf("Enter the second number: ");

scanf("%d",&no2);

//Printing the output addition for the numbers

printf("\nAddition of %d + %d",no1,no2);

printf(" = %d",(no1+no2 ));

//Printing the output substraction for the numbers

printf("\nSubstraction of %d - %d",no1,no2);

printf(" = %d",(no1-no2));

//Printing the output multipliccation for the numbers

printf("\nMultiplication of %d X %d",no1,no2);

printf(" = %d",(no1*no2 ));

//Printing the output division for the numbers

printf("\nDivision of %d / %d",no1,no2);

printf(" = %d",(no1/no2 ));

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no1 = it will hold the integer value.
no2 = it will hold the integer value.

Input number from the user.

Program Logic Code and print the output.

C Program to Print Second Largest & Second Smallest Array Element

In this tutorial, we will learn to create a C program that will Print Second Largest & Second Smallest Array Element using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in C Programming.

Print Second Largest & Second Smallest Array Element:-

As we all know array is a collection of similar data type elements. In an array, only one variable is declared which can store multiple values. First will take the number of elements of an array from the user. Then will take the elements from the user for the array. And at last, Print Second Largest & Second Smallest Array Element using C Programming Language.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the array size from the user.

3. Taking the elements of the array.

4. Sorting the array.

5. Printing the results.

6. End program.

1. Declaring the variables for the program.

2. Taking the array size from the user.

3. Taking the elements of the array.

4. Sorting the array.

5. Printing the results.

6. End program.

Program:-

Print Second Largest & Second Smallest Array Element

#include <stdio.h>

int main()
{
    //Declaring the variable.
    int n;
    int a[n]; //Declaration of array.
    
    //taking array size by the user.
    printf("Enter the number of elements:");
    scanf("%d",&n);
    //taking array elements by the user
    printf("Enter the array elements :");
    
    //taking input for the array
    for(int i=0;i<n;i++)
    {
        scanf("%d",&a[i]);
    }
    for(int i=0;i<n;i++)  //Sorting The Array
    {
        int flag;
        for(int j=i+1; j<n ;j++)
        {
            if(a[i]<a[j])
            {
                flag=a[i];
                a[i]=a[j];
                a[j]=flag;
            }
        }
    }
    printf("The second smallest element is %d",a[n-2]);  
    //Accessing the smallest element
    printf("\n");
    printf("The second largest element is %d",a[1]);      
    //Accessing the largest element
    return 0;
}

#include <stdio.h>

int main()

{

//Declaring the variable.

int n;

int a[n]; //Declaration of array.

//taking array size by the user.

printf("Enter the number of elements:");

scanf("%d",&n);

//taking array elements by the user

printf("Enter the array elements :");

//taking input for the array

for(int i=0;i<n;i++)

{

scanf("%d",&a[i]);

}

for(int i=0;i<n;i++) //Sorting The Array

{

int flag;

for(int j=i+1; j<n ;j++)

{

if(a[i]<a[j])

{

flag=a[i];

a[i]=a[j];

a[j]=flag;

}

printf("The second smallest element is %d",a[n-2]);

//Accessing the smallest element

printf("\n");

printf("The second largest element is %d",a[1]);

//Accessing the largest element

return 0;

}

Output:-

In the above program, we have first initialized the required variable

a[n] = it will hold the elements in an array.
n = it will hold the number of elements in an array.
i = it will hold the integer value to control the array.
flag = it will hold the integer value.

Taking input from the user in an array number of elements in the array.

Sorting the array,

Printing the results.

C Program to Calculate Telephone Call Bills

In this tutorial, we will learn to create a C program that will Calculate Telephone Call Bills using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
While loop in C programming.
Arithmetic operations in C Programming.

Program to Calculate Telephone Call Bills

In c programming, it is possible to take numerical input from the user and calculate Telephone Call Bills with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy. But today we will Calculate Telephone Call Bills using c programming. As per the following rule:

Minimum Rs. 200 for up to 100 calls.
Plus Rs. 0.60 per call for the next 50 calls.
Plus Rs. 0.50 per call for the next 50 calls.
Plus Rs. 0.40 per call for any call beyond 200 calls.

With the help of this program, we can Calculate Telephone Call Bills.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input minutes in number from the user.

3. Checking the minutes used.

4. Checking the plans.

5. Printing the result numbers.

6. End the program.

1. Declaring the variables for the program.

2. Taking the input minutes in number from the user.

3. Checking the minutes used.

4. Checking the plans.

5. Printing the result numbers.

6. End the program.

Program to Calculate Telephone Call Bills:-

#include <stdio.h>

int main()
{
    //declaring the variable for the program
    int calls;
    float bill;

   //showing the message for the input
    printf("Enter number of calls :");
   //scanning the minutes number
    scanf("%d", &calls);

    //cheking the minutes with the plans
    if (calls <= 100)
    {
        bill = 200;
    }
    else if (calls > 100 && calls <= 150)
    {
        calls = calls - 100;
        bill = 200+(0.60 *calls);
    }
    else if (calls > 150 && calls <= 200)
    {
        calls = calls - 150;
        bill = 200+(0.60 *50) + (0.50 *calls);
    }
    else
    {
        calls = calls - 200;
        bill = 200 + (0.60 * 50) + (0.50 * 50) + (0.40 * calls);
    }

    //printing the calculated bill for the callings
    printf("Your bill is Rs. %0.2f", bill);

    return 0;
}

#include <stdio.h>

int main()

{

//declaring the variable for the program

int calls;

float bill;

//showing the message for the input

printf("Enter number of calls :");

//scanning the minutes number

scanf("%d", &calls);

//cheking the minutes with the plans

if (calls <= 100)

{

bill = 200;

}

else if (calls > 100 && calls <= 150)

{

calls = calls - 100;

bill = 200+(0.60 *calls);

}

else if (calls > 150 && calls <= 200)

{

calls = calls - 150;

bill = 200+(0.60 *50) + (0.50 *calls);

}

else

{

calls = calls - 200;

bill = 200 + (0.60 * 50) + (0.50 * 50) + (0.40 * calls);

}

//printing the calculated bill for the callings

printf("Your bill is Rs. %0.2f", bill);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

calls = it will hold the integer value for the calls in minutes.
bill = it will hold the floating value for the bills.

Input number from the user.

Program Logic Code.

Printing output for bill generated.

C Program to Print Sum of Even & Product of Odd Digit

In this tutorial, we will learn to create a C program that will Print Sum of Even & Product of Odd Digit using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
While loop in C programming.
Arithmetic operations in C Programming.

Program to Print Sum of Even & Product of Odd Digit

In c programming, it is possible to take numerical input from the user and Print Sum of Even & Product of Odd Digit with the help of a very small amount of code. The C language has many types of header libraries which has supported function in them with the help of these files the programming is easy.

With the help of this program, we can Print Sum of Even & Product of Odd Digit.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the sum of even numbers.

4. Calculating the product of the odd numbers.

5. Printing the result numbers.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the sum of even numbers.

4. Calculating the product of the odd numbers.

5. Printing the result numbers.

Program to Print Sum of Even & Product of Odd Digit:-

#include<stdio.h>

int main()
{
    //declaring the variable for the program 
    
    int no, evenSum=0, oddProd=1, rem, temp;
    //showing the message for the input 
    printf("Enter any number: ");
    //scanning the number
    scanf("%d", &no);
    
    //using while loop to sort even odd numbers and calculating
    //the sum nad products of digits of a number
    while(no>0)
    {
        rem = no%10;
        if(rem%2==0)
            evenSum = evenSum + rem;
        else
            oddProd = oddProd * rem;
        no = no/10;
    }
    
    //Printing the output of the program
    printf("\nSum of Even Digit = %d", evenSum);
    printf("\nProduct of Odd Digit = %d", oddProd);
 
    return 0;
}

#include<stdio.h>

int main()

{

//declaring the variable for the program

int no, evenSum=0, oddProd=1, rem, temp;

//showing the message for the input

printf("Enter any number: ");

//scanning the number

scanf("%d", &no);

//using while loop to sort even odd numbers and calculating

//the sum nad products of digits of a number

while(no>0)

{

rem = no%10;

if(rem%2==0)

evenSum = evenSum + rem;

else

oddProd = oddProd * rem;

no = no/10;

}

//Printing the output of the program

printf("\nSum of Even Digit = %d", evenSum);

printf("\nProduct of Odd Digit = %d", oddProd);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

evenSum = it will hold the integer value for the sum of numbers.
oddProd = it will hold the integer value for the product of the numbers.
temp = it will hold the temporary integer value.
rem = it will hold the integer value of the remainder.
no = it will hold the integer value of the input.

Input number from the user.

Program Logic Code.

Printing output for sum and the product.

C Program to Round off Floating point Number

In this tutorial, we will learn to create a C program that will Round off Floating-point Numbers in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
Conditional Statements in c programming.

Round off Floating point Number.

As we all know the c programming is a very powerful language. In the c programming language, we have many pre-defined functions for arithmetic operations. But today we will Round off the Floating-point Numbers using the c programming language.

With C programming we can make many arithmetics series with just a little code.

With the help of this program, we can Round off Floating-point Numbers.

Algorithm:-

1. Declare the variables for the program.
 
2. Take the input number from the user.
 
3. Pass that number to a if condition.
 
4. Calculate the round of number.
 
5. Print the round of that number.
 
6. End the program.

1. Declare the variables for the program.

2. Take the input number from the user.

3. Pass that number to a if condition.

4. Calculate the round of number.

5. Print the round of that number.

6. End the program.

Program to Round off Floating point Number:-

#include<stdio.h>
int main()
{
    //declaring the variables for the program 
    float num;
    int flag, roundNum, tempNum;
    
    //Taking the input number from the user 
    printf("Enter the number: ");
    scanf("%f", &num);
   
   //checking the number greater than zero
    if(num>0)
    {
        tempNum = num*10;
        flag = tempNum%10;
        if(flag>=5)
        {
            roundNum = num;
            roundNum++;
        }
        else
        {
            roundNum = num;
        }
        //printing rounded positive number
        printf("\nWhole number after rounding off the given real number = %d", roundNum);
    }
    //checking the number smaller than zero
    else if(num<0)
    {
        num = -(num);
        tempNum = num*10;
        flag = tempNum%10;
        if(flag>=5)
        {
            roundNum = num;
            roundNum--;
        }
        else
        {
            roundNum = num;
        }
        //printing rounded negative number
        printf("\nWhole number after rounding off the given real number = -%d", roundNum);
    }
    else
    //printing given number in output
    {
        printf("\nThe given number is 0");
    }
    return 0;
}

#include<stdio.h>

int main()

{

//declaring the variables for the program

float num;

int flag, roundNum, tempNum;

//Taking the input number from the user

printf("Enter the number: ");

scanf("%f", &num);

//checking the number greater than zero

if(num>0)

{

tempNum = num*10;

flag = tempNum%10;

if(flag>=5)

{

roundNum = num;

roundNum++;

}

else

{

roundNum = num;

}

//printing rounded positive number

printf("\nWhole number after rounding off the given real number = %d", roundNum);

}

//checking the number smaller than zero

else if(num<0)

{

num = -(num);

tempNum = num*10;

flag = tempNum%10;

if(flag>=5)

{

roundNum = num;

roundNum--;

}

else

{

roundNum = num;

}

//printing rounded negative number

printf("\nWhole number after rounding off the given real number = -%d", roundNum);

}

else

//printing given number in output

{

printf("\nThe given number is 0");

}

return 0;

}

Output:-

Positive round-of:-

Negative round-of:-

In the above program, we have first initialized the required variable.

num = it will hold the floating number value.
flag = it will hold the integer value.
roundNum = it will hold the integer value.
tempNum = it will hold the integer value.

Checking the number greater than zero.

Checking the number smaller than zero.

Printing the number equal to zero.