Category Archives: C Programs

C Programs

C Program to Convert Octal to Binary

In this tutorial, we will learn to create a C program that will Convert Octal to Binary in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Octal to Binary:-

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in octal from the user and convert it into binary. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Octal to binary.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from from the user in octal for the program. 

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from from the user in octal for the program.

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.

4. Print the Result.

5. End the program.

Program to Convert Octal to Binary:-

#include <math.h>
#include <stdio.h>
long long convert(int oct);
int main() 
{
    //decalring the variable for the program
    int oct;
    //taking input from the user in octal number 
    printf("Enter an octal number: ");
    //scanning the octal number.
    scanf("%d", &oct);
    //result printing after convertion
    printf("%d in octal = %lld in binary", oct, convert(oct));
    return 0;
}
//function for converting the ocatl to decimal and then to binary.
long long convert(int oct) {
    int dec = 0, i = 0;
    long long bin = 0;

    // converting octal to decimal
    while (oct != 0) {
        dec += (oct % 10) * pow(8, i);
        ++i;
        oct /= 10;
    }
    i = 1;

   // converting decimal to binary
    while (dec != 0) {
        bin += (dec % 2) * i;
        dec /= 2;
        i *= 10;
    }
    return bin;
}

#include <math.h>

#include <stdio.h>

long long convert(int oct);

int main()

{

//decalring the variable for the program

int oct;

//taking input from the user in octal number

printf("Enter an octal number: ");

//scanning the octal number.

scanf("%d", &oct);

//result printing after convertion

printf("%d in octal = %lld in binary", oct, convert(oct));

return 0;

}

//function for converting the ocatl to decimal and then to binary.

long long convert(int oct) {

int dec = 0, i = 0;

long long bin = 0;

// converting octal to decimal

while (oct != 0) {

dec += (oct % 10) * pow(8, i);

++i;

oct /= 10;

}

i = 1;

// converting decimal to binary

while (dec != 0) {

bin += (dec % 2) * i;

dec /= 2;

i *= 10;

}

return bin;

}

Output:-

In the above program, we have first initialized the required variable.

oct = in will hold the integer value.

Taking the input.

Octal to decimal.

Decimal to binary.

Printing the binary data.

Main Function.

C Program to Convert Octal to Hexadecimal

In this tutorial, we will learn to create a C program that will Convert Octal to Hexadecimal in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Octal to Hexadecimal:-

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in octal from the user and convert it into hexadecimal. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Octal to Hexadecimal.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from from the user in octal for the program. 

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from from the user in octal for the program.

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.

4. Print the Result.

5. End the program.

Program to Convert Octal to Hexadecimal:-

#include <stdio.h>  
#include<string.h>  
int main()  
{  
  //declaring the variable for the program
  int octaltobinary[]={0,1,10,11,100,101,110,111};  
  char hexadecimal[10];  
   char hex[10];  
  long int binary=0;  
  int octal;  
  int rem=0;  
  int position=1;  
  int len=0;  
   int k=0;  
   //taking input in the octal number
  printf("Enter a octal number");  
  scanf("%d",&octal);  
  // Converting octal number into a binary number.    
   while(octal!=0)  
  {  
      rem=octal%10;  
      binary=octaltobinary[rem]*position+binary;  
      octal=octal/10;  
      position=position*1000;  
  }  
  printf("The binary number is : %ld",binary);  
    
  // Converting binary number into a hexadecimal number.  
  while(binary > 0)  
    {  
        rem = binary % 10000;  
        switch(rem)  
        {  
            case 0:  
                strcat(hexadecimal, "0");  
                break;  
            case 1:  
                strcat(hexadecimal, "1");  
                break;  
            case 10:  
                strcat(hexadecimal, "2");  
                break;  
            case 11:  
                strcat(hexadecimal, "3");  
                break;  
            case 100:  
                strcat(hexadecimal, "4");  
                break;  
            case 101:  
                strcat(hexadecimal, "5");  
                break;  
            case 110:  
                strcat(hexadecimal, "6");  
                break;  
            case 111:  
                strcat(hexadecimal, "7");  
                break;  
            case 1000:  
                strcat(hexadecimal, "8");  
                break;  
            case 1001:  
                strcat(hexadecimal, "9");  
                break;  
            case 1010:  
                strcat(hexadecimal, "A");  
                break;  
            case 1011:  
                strcat(hexadecimal, "B");  
                break;  
            case 1100:  
                strcat(hexadecimal, "C");  
                break;  
            case 1101:  
                strcat(hexadecimal, "D");  
                break;  
            case 1110:  
                strcat(hexadecimal, "E");  
                break;  
            case 1111:  
                strcat(hexadecimal, "F");  
            break;  
        }  
len=len+1;  
        binary /= 10000;  
    }  
  for(int i=len-1;i>=0;i--)  
{  
    hex[k]=hexadecimal[i];  
    k++;  
}  
hex[len]='\0';  
//printing the output in the hexadecimal 
printf("\nThe hexadecimal number is :");  
for(int i=0; hex[i]!='\0';i++)  
{  
    printf("%c",hex[i]);  
}  
  
    return 0;  
}

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#include <stdio.h>

#include<string.h>

int main()

{

//declaring the variable for the program

int octaltobinary[]={0,1,10,11,100,101,110,111};

char hexadecimal[10];

char hex[10];

long int binary=0;

int octal;

int rem=0;

int position=1;

int len=0;

int k=0;

//taking input in the octal number

printf("Enter a octal number");

scanf("%d",&octal);

// Converting octal number into a binary number.

while(octal!=0)

{

rem=octal%10;

binary=octaltobinary[rem]*position+binary;

octal=octal/10;

position=position*1000;

}

printf("The binary number is : %ld",binary);

// Converting binary number into a hexadecimal number.

while(binary > 0)

{

rem = binary % 10000;

switch(rem)

{

case 0:

strcat(hexadecimal, "0");

break;

case 1:

strcat(hexadecimal, "1");

break;

case 10:

strcat(hexadecimal, "2");

break;

case 11:

strcat(hexadecimal, "3");

break;

case 100:

strcat(hexadecimal, "4");

break;

case 101:

strcat(hexadecimal, "5");

break;

case 110:

strcat(hexadecimal, "6");

break;

case 111:

strcat(hexadecimal, "7");

break;

case 1000:

strcat(hexadecimal, "8");

break;

case 1001:

strcat(hexadecimal, "9");

break;

case 1010:

strcat(hexadecimal, "A");

break;

case 1011:

strcat(hexadecimal, "B");

break;

case 1100:

strcat(hexadecimal, "C");

break;

case 1101:

strcat(hexadecimal, "D");

break;

case 1110:

strcat(hexadecimal, "E");

break;

case 1111:

strcat(hexadecimal, "F");

break;

}

len=len+1;

binary /= 10000;

}

for(int i=len-1;i>=0;i--)

{

hex[k]=hexadecimal[i];

k++;

}

hex[len]='\0';

//printing the output in the hexadecimal

printf("\nThe hexadecimal number is :");

for(int i=0; hex[i]!='\0';i++)

{

printf("%c",hex[i]);

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

hexadecimal[] = it will hold the character value for the program.
octaltobinary[] = in will hold the integer value.
i = it will hold the integer value.

Taking the input.

Octal to Binary.

Binary to Hexadecimal.

Printing the Decimal data.

C Program to Convert Hexadecimal to Binary

In this tutorial, we will learn to create a C program that will Convert Hexadecimal to Binary in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Hexadecimal to Binary:-

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in hexadecimal from the user and convert it into binary. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Hexadecimal to Binary.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from in hexa for the program. 

3. Passing that input to functions.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from in hexa for the program.

3. Passing that input to functions.

4. Print the Result.

5. End the program.

Program to Convert Hexadecimal to Binary:-

/*
C Program to Convert Hexadecimal to Binary 
*/
#include <stdio.h>
// function to convert Hexadecimal to Binary Number
void HexToBin(char* hexdec)
{
	long int i = 0;
	while (hexdec[i]) {
		switch (hexdec[i]) {
		case '0':
			printf("0000");
			break;
		case '1':
			printf("0001");
			break;
		case '2':
			printf("0010");
			break;
		case '3':
			printf("0011");
			break;
		case '4':
			printf("0100");
			break;
		case '5':
			printf("0101");
			break;
		case '6':
			printf("0110");
			break;
		case '7':
			printf("0111");
			break;
		case '8':
			printf("1000");
			break;
		case '9':
			printf("1001");
			break;
		case 'A':
		case 'a':
			printf("1010");
			break;
		case 'B':
		case 'b':
			printf("1011");
			break;
		case 'C':
		case 'c':
			printf("1100");
			break;
		case 'D':
		case 'd':
			printf("1101");
			break;
		case 'E':
		case 'e':
			printf("1110");
			break;
		case 'F':
		case 'f':
			printf("1111");
			break;
		default:
			printf("\nInvalid hexadecimal digit %c",
				hexdec[i]);
		}
		i++;
	}
}
// main fucntion code
int main()
{
	// Get the Hexadecimal number
	char hexdec[100] = "1AC5";
	// Convert HexaDecimal to Binary
	printf("\nEquivalent Binary value is : ");
	HexToBin(hexdec);
}

C Program to Convert Hexadecimal to Binary

#include <stdio.h>

// function to convert Hexadecimal to Binary Number

void HexToBin(char* hexdec)

{

long int i = 0;

while (hexdec[i]) {

switch (hexdec[i]) {

case '0':

printf("0000");

break;

case '1':

printf("0001");

break;

case '2':

printf("0010");

break;

case '3':

printf("0011");

break;

case '4':

printf("0100");

break;

case '5':

printf("0101");

break;

case '6':

printf("0110");

break;

case '7':

printf("0111");

break;

case '8':

printf("1000");

break;

case '9':

printf("1001");

break;

case 'A':

case 'a':

printf("1010");

break;

case 'B':

case 'b':

printf("1011");

break;

case 'C':

case 'c':

printf("1100");

break;

case 'D':

case 'd':

printf("1101");

break;

case 'E':

case 'e':

printf("1110");

break;

case 'F':

case 'f':

printf("1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

}

i++;

}

// main fucntion code

int main()

{

// Get the Hexadecimal number

char hexdec[100] = "1AC5";

// Convert HexaDecimal to Binary

printf("\nEquivalent Binary value is : ");

HexToBin(hexdec);

}

Output:-

In the above program, we have first initialized the required variable.

hex[100] = it will hold the Hexa value for the program.

Hexa to binary

Printing the binary data.

Main function.

C Program to Convert Hexadecimal to Decimal

In this tutorial, we will learn to create a C program that will Convert Hexadecimal to Decimal in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Hexadecimal to Decimal:-

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in hexadecimal from the user and convert it into Decimal. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Hexadecimal to Decimal.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from from the user in hexa decimal for the program. 

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from from the user in hexa decimal for the program.

3. Passing that input to the string function.

4. Pass that number to a for loop for convertion.

4. Print the Result.

5. End the program.

Program to Convert Hexadecimal to Decimal:-

/*
C Program to Convert Hexadecimal to DECIMAL
*/
#include <stdio.h>
#include <math.h>
#include <string.h>
#define ARRAY_SIZE  20
int main()
{
    /* Declaring the variables for the program */
    char hex[ARRAY_SIZE];
    long long decimal = 0, base = 1;
    int i = 0, value, length;
    /* Get hexadecimal value from user */
    printf("Enter hexadecimal number: ");
    fflush(stdin);
    fgets(hex,ARRAY_SIZE,stdin);
    length = strlen(hex);
    /* Converting the Hexa decimal to the decimal */
    for(i = length--; i >= 0; i--)
    {
        if(hex[i] >= '0' && hex[i] <= '9')
        {
            decimal += (hex[i] - 48) * base;
            base *= 16;
        }
        else if(hex[i] >= 'A' && hex[i] <= 'F')
        {
            decimal += (hex[i] - 55) * base;
            base *= 16;
        }
        else if(hex[i] >= 'a' && hex[i] <= 'f')
        {
            decimal += (hex[i] - 87) * base;
            base *= 16;
        }
    }
    //PRINTING THE HEXADECIMAL NUMBER TO THE USER
    printf("\nHexadecimal number = %s", hex);
    //PRINTING THE DECIMAL NUMBER TO THE USER
    printf("Decimal number = %lld\n", decimal);
    return 0;
}

C Program to Convert Hexadecimal to DECIMAL

#include <stdio.h>

#include <math.h>

#include <string.h>

#define ARRAY_SIZE 20

int main()

{

/* Declaring the variables for the program */

char hex[ARRAY_SIZE];

long long decimal = 0, base = 1;

int i = 0, value, length;

/* Get hexadecimal value from user */

printf("Enter hexadecimal number: ");

fflush(stdin);

fgets(hex,ARRAY_SIZE,stdin);

length = strlen(hex);

/* Converting the Hexa decimal to the decimal */

for(i = length--; i >= 0; i--)

{

if(hex[i] >= '0' && hex[i] <= '9')

{

decimal += (hex[i] - 48) * base;

base *= 16;

}

else if(hex[i] >= 'A' && hex[i] <= 'F')

{

decimal += (hex[i] - 55) * base;

base *= 16;

}

else if(hex[i] >= 'a' && hex[i] <= 'f')

{

decimal += (hex[i] - 87) * base;

base *= 16;

}

//PRINTING THE HEXADECIMAL NUMBER TO THE USER

printf("\nHexadecimal number = %s", hex);

//PRINTING THE DECIMAL NUMBER TO THE USER

printf("Decimal number = %lld\n", decimal);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

hex[] = it will hold the Hexa value for the program.
i = it will hold the integer value.

Taking the input.

Hexadecimal to Decimal.

Printing the Decimal data.

C Program to Convert Hexadecimal to Octal

In this tutorial, we will learn to create a C program that will Convert Hexadecimal to Octal in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Hexadecimal to Octal:-

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in hexadecimal from the user and convert it into octal. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Hexadecimal to Octal.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from in hexa for the program. 

3. Passing that input to functions.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from in hexa for the program.

3. Passing that input to functions.

4. Print the Result.

5. End the program.

Program to Convert Hexadecimal to Octal:-

/* C Program to Convert Hexadecimal to Octal */
#include <math.h>
#include <stdio.h>
#include <string.h>
// Function to convert HexaDecimal to Binary
long long int hex_to_bin(char hex[])
{
	long long int bin, place;
	int i = 0, rem, val;
	bin = 0ll;
	place = 0ll;
	// Hexadecimal to binary conversion
	for (i = 0; hex[i] != '\0'; i++) {
		bin = bin * place;

		switch (hex[i]) {
		case '0':
			bin += 0;
			break;
		case '1':
			bin += 1;
			break;
		case '2':
			bin += 10;
			break;
		case '3':
			bin += 11;
			break;
		case '4':
			bin += 100;
			break;
		case '5':
			bin += 101;
			break;
		case '6':
			bin += 110;
			break;
		case '7':
			bin += 111;
			break;
		case '8':
			bin += 1000;
			break;
		case '9':
			bin += 1001;
			break;
		case 'a':
		case 'A':
			bin += 1010;
			break;
		case 'b':
		case 'B':
			bin += 1011;
			break;
		case 'c':
		case 'C':
			bin += 1100;
			break;
		case 'd':
		case 'D':
			bin += 1101;
			break;
		case 'e':
		case 'E':
			bin += 1110;
			break;
		case 'f':
		case 'F':
			bin += 1111;
			break;
		default:
			printf("Invalid hexadecimal input.");
		}
		place = 10000;
	}
	return bin;
}
// Function to convert Binary to Octal
long long int bin_to_oct(long long bin)
{
	long long int octal, place;
	int i = 0, rem, val;
	octal = 0ll;
	place = 0ll;
	place = 1;
	// Binary to octal conversion
	while (bin > 0) {
		rem = bin % 1000;

		switch (rem) {
		case 0:
			val = 0;
			break;
		case 1:
			val = 1;
			break;
		case 10:
			val = 2;
			break;
		case 11:
			val = 3;
			break;
		case 100:
			val = 4;
			break;
		case 101:
			val = 5;
			break;
		case 110:
			val = 6;
			break;
		case 111:
			val = 7;
			break;
		}
		octal = (val * place) + octal;
		bin /= 1000;
		place *= 10;
	}
	return octal;
}
// Function to Convert
// Hexadecimal Number to Octal Number
long long int hex_to_oct(char hex[])
{
	long long int octal, bin;
	// convert HexaDecimal to Binary
	bin = hex_to_bin(hex);

	// convert Binary to Octal
	octal = bin_to_oct(bin);
	return octal;
}
int main()
{
// Get the hexadecimal number
	char hex[20] = "1AC";
// convert hexadecimal to octal
	printf("Equivalent Octal Value = %lld",
hex_to_oct(hex));
	return 0;
}

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/* C Program to Convert Hexadecimal to Octal */

#include <math.h>

#include <stdio.h>

#include <string.h>

// Function to convert HexaDecimal to Binary

long long int hex_to_bin(char hex[])

{

long long int bin, place;

int i = 0, rem, val;

bin = 0ll;

place = 0ll;

// Hexadecimal to binary conversion

for (i = 0; hex[i] != '\0'; i++) {

bin = bin * place;

switch (hex[i]) {

case '0':

bin += 0;

break;

case '1':

bin += 1;

break;

case '2':

bin += 10;

break;

case '3':

bin += 11;

break;

case '4':

bin += 100;

break;

case '5':

bin += 101;

break;

case '6':

bin += 110;

break;

case '7':

bin += 111;

break;

case '8':

bin += 1000;

break;

case '9':

bin += 1001;

break;

case 'a':

case 'A':

bin += 1010;

break;

case 'b':

case 'B':

bin += 1011;

break;

case 'c':

case 'C':

bin += 1100;

break;

case 'd':

case 'D':

bin += 1101;

break;

case 'e':

case 'E':

bin += 1110;

break;

case 'f':

case 'F':

bin += 1111;

break;

default:

printf("Invalid hexadecimal input.");

}

place = 10000;

}

return bin;

}

// Function to convert Binary to Octal

long long int bin_to_oct(long long bin)

{

long long int octal, place;

int i = 0, rem, val;

octal = 0ll;

place = 0ll;

place = 1;

// Binary to octal conversion

while (bin > 0) {

rem = bin % 1000;

switch (rem) {

case 0:

val = 0;

break;

case 1:

val = 1;

break;

case 10:

val = 2;

break;

case 11:

val = 3;

break;

case 100:

val = 4;

break;

case 101:

val = 5;

break;

case 110:

val = 6;

break;

case 111:

val = 7;

break;

}

octal = (val * place) + octal;

bin /= 1000;

place *= 10;

}

return octal;

}

// Function to Convert

// Hexadecimal Number to Octal Number

long long int hex_to_oct(char hex[])

{

long long int octal, bin;

// convert HexaDecimal to Binary

bin = hex_to_bin(hex);

// convert Binary to Octal

octal = bin_to_oct(bin);

return octal;

}

int main()

{

// Get the hexadecimal number

char hex[20] = "1AC";

// convert hexadecimal to octal

printf("Equivalent Octal Value = %lld",

hex_to_oct(hex));

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

hex[20] = it will hold the Hexa value for the program.

Hexa to binary

Binary to octal.

Hexa to octal.

Main function.

C Program to Convert Inches to Centimeters

In this tutorial, we will learn to create a C program that will Convert Inches to Centimeters in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Inches to Centimeters

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in inches from the user and convert it into centimeters. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Inches into Centimeters.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from the user for the program. 

3. Passing that input for calculations.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from the user for the program.

3. Passing that input for calculations.

4. Print the Result.

5. End the program.

Program to Convert Inches to Centimeters:-

/* Program to convert the inch input into the Centimeters output */ 
#include<stdio.h>
int main() 
{ 
    /*declaring the variables for the program */ 
    float inch, cm;
    
    /*taking the input from the user in inch*/ 
    printf("Enter length in Inch: ");
    
    /*scanning the input from the user*/ 
    scanf("%f", &inch); 
    
    /*Coverting the inch into Centimeters.*/ 
    cm = inch * 2.54; 
    
    /* 
    Printing the result in Centimeters converted with the help of program
    */ 
    printf("Equivalent length in Centimeters = %0.2f", cm); 
    
    return 0;
}

/* Program to convert the inch input into the Centimeters output */

#include<stdio.h>

int main()

{

/*declaring the variables for the program */

float inch, cm;

/*taking the input from the user in inch*/

printf("Enter length in Inch: ");

/*scanning the input from the user*/

scanf("%f", &inch);

/*Coverting the inch into Centimeters.*/

cm = inch * 2.54;

Printing the result in Centimeters converted with the help of program

printf("Equivalent length in Centimeters = %0.2f", cm);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

inch = it will hold the float value for the program as an input from the user.
cm = it will hold the float value that will hold the grams converted in the program.

Taking the input from the user in the form of inch.

Scanning the input.

Converting the inch into centimeters.

Printing the converted output from kilograms to grams.

C Program to Convert Kilogram to Gram

In this tutorial, we will learn to create a C program that will Convert Kilogram to Gram in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Program to Convert Kilogram to Gram

As we all know the c is a very powerful language. With the help of c programming language, we can make many programs. We cal perform many input-output operations using c programming. In today’s tutorial, we take the input in kilograms from the user and convert it into grams. With the help of c programming, we can perform many conversion operations.

With the help of this program, we can Convert Kilogram to Gram.

Algorithm:-

1. Declare the variables for the program. 

2. Takeing the input number from the user for the program. 

3. Passing that input for calculations.  

4. Print the Result. 

5. End the program.

1. Declare the variables for the program.

2. Takeing the input number from the user for the program.

3. Passing that input for calculations.

4. Print the Result.

5. End the program.

Program to Convert Kilogram to Gram:-

/*
Program to convert the kilo-grams input into the grams output
*/ 
#include<stdio.h>
int main()
{
    /*declaring the variables for the program */
    float kg, g;
    /*taking the input from the user in kilo-grams*/
    printf("Enter weight in Kilogram: ");
    /*scanning the input from the user*/
    scanf("%f", &kg);
    /*Coverting the kilo-grams into grams.*/
    g = kg*1000;
    /*
    Printing the result in grams converted with the help of program
    */
    printf("Equivalent weight in Gram = %0.2f", g);
  
    return 0;
}

Program to convert the kilo-grams input into the grams output

#include<stdio.h>

int main()

{

/*declaring the variables for the program */

float kg, g;

/*taking the input from the user in kilo-grams*/

printf("Enter weight in Kilogram: ");

/*scanning the input from the user*/

scanf("%f", &kg);

/*Coverting the kilo-grams into grams.*/

g = kg*1000;

Printing the result in grams converted with the help of program

printf("Equivalent weight in Gram = %0.2f", g);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

kg = it will hold the float value for the program as an input from the user.
g = it will hold the float value that will hold the grams converted in the program.

Taking the input from the user in the form of kilograms.

Converting the kilograms to grams.

Printing the converted output from kilograms to grams.

C Program to Pass Array to Function

In this tutorial, we will learn to create a C program that will Pass Array to Function in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in c programming.
String functions of c programming.

Program to Pass Array to Function

As we all know the array is a collection of similar data types. In an array, only one variable is declared which can store multiple values. First, we will declare the input array for the program.

Then we will pass that array to a function for the calculation.

Then we will add the elements of using the for a loop.

With the help of this program, we can Pass Array to Function.

Algorithm:-

1. Declare the variables for the program. 

2. Give the input array for the program. 

3. Pass that array to a user-defined function. 

4. Adding that array in function using for loop. 

5. Print the Result. 

6. End the program.

1. Declare the variables for the program.

2. Give the input array for the program.

3. Pass that array to a user-defined function.

4. Adding that array in function using for loop.

5. Print the Result.

6. End the program.

Program to Pass Array to Function:-

/*
Program to adding the array elements by passing to a function
*/ 
#include <stdio.h>
/*
user defined function for the addtion of the array
*/
float Sumarry(float no[]);

int main()
{
    //declaring the variables for the program 
  float result, no[] = {23.4, 55, 22.6, 3, 40.5, 18};

  // no array is passed to Sumarry()
  result = Sumarry(no); 
  //printing the result
  printf("Result = %.2f", result);
  return 0;
}
//body of the user defined function 
float Sumarry(float no[]) {
  float sum = 0.0;

  for (int i = 0; i < 6; ++i) {
    sum += no[i];
  }
  //returning the sum of array from the function
  return sum;
}

Program to adding the array elements by passing to a function

#include <stdio.h>

user defined function for the addtion of the array

float Sumarry(float no[]);

int main()

{

//declaring the variables for the program

float result, no[] = {23.4, 55, 22.6, 3, 40.5, 18};

// no array is passed to Sumarry()

result = Sumarry(no);

//printing the result

printf("Result = %.2f", result);

return 0;

}

//body of the user defined function

float Sumarry(float no[]) {

float sum = 0.0;

for (int i = 0; i < 6; ++i) {

sum += no[i];

}

//returning the sum of array from the function

return sum;

}

Output:-

In the above program, we have first initialized the required variable.

no[] = it will hold the float value array.
result = it will hold the float value.
sum = it will hold the float value.
i = it will hold the integer value for the loop control.

User-defined function declaration for the addition of array.

Body of the user-defined function.

Printing the output.

C Program to print Address of Variable

In this tutorial, we will learn to create a C program that will Print the Address of the variable in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.

Print the Address of the variable.

As we all know the c programming is a very powerful language. In the c programming language, we have many pre-defined functions for arithmetic operations, string functions. But today we will print the address of the variable taken input from the given number using the c programming language.

With the help of this program, we can Print the Address of the variable.

Algorithm:-

1. Declare the variables for the program.
 
2. Take the input number from the user.
 
3. Print the number.
 
4. Print the address.
 
5. End the program.

1. Declare the variables for the program.

2. Take the input number from the user.

3. Print the number.

4. Print the address.

5. End the program.

Program to Print the Address of variable:-

/*
C Program to print Address of Variable
*/
#include<stdio.h>

int main()
{
    //declaring the variable for the program 
     int no1, no2, no3, sum=0;
      /*
    sending message on the console to take a number1 in input on a variable
    */
    printf("Enter any number to store in \"no1\" variable: ");
    scanf("%d", &no1);
     /*
    sending message on the console to take a number2 in input on a variable
    */
    printf("Enter any number to store in \"no2\" variable: ");
    scanf("%d", &no2);
     /*
    sending message on the console to take a number3 in input on a variable
    */
    printf("Enter any number to store in \"no3\" variable: ");
    scanf("%d", &no3);
    //printing the value of the variable1 
    printf("\nValue of no1 = %d", no1);
    //printing the address of the variable1
    printf("\nAddress of no1 = %u", &no1);
    //printing the value of the variable 2
    printf("\nValue of no2 = %d", no2);
    //printing the address of the variable 2
    printf("\nAddress of no2 = %u", &no2);
    //printing the value of the variable 3
    printf("\nValue of no3 = %d", no3);
    //printing the address of the variable 3
    printf("\nAddress of no3 = %u", &no3);
    
    sum = no1+no2+no3;
    //printing the value of the variable sum
    printf("\n\nValue of sum = %d", sum);
    //printing the address of the variable sum
    printf("\nAddress of sum = %u", &sum);
    
    return 0;
}

C Program to print Address of Variable

#include<stdio.h>

int main()

{

//declaring the variable for the program

int no1, no2, no3, sum=0;

sending message on the console to take a number1 in input on a variable

printf("Enter any number to store in \"no1\" variable: ");

scanf("%d", &no1);

sending message on the console to take a number2 in input on a variable

printf("Enter any number to store in \"no2\" variable: ");

scanf("%d", &no2);

sending message on the console to take a number3 in input on a variable

printf("Enter any number to store in \"no3\" variable: ");

scanf("%d", &no3);

//printing the value of the variable1

printf("\nValue of no1 = %d", no1);

//printing the address of the variable1

printf("\nAddress of no1 = %u", &no1);

//printing the value of the variable 2

printf("\nValue of no2 = %d", no2);

//printing the address of the variable 2

printf("\nAddress of no2 = %u", &no2);

//printing the value of the variable 3

printf("\nValue of no3 = %d", no3);

//printing the address of the variable 3

printf("\nAddress of no3 = %u", &no3);

sum = no1+no2+no3;

//printing the value of the variable sum

printf("\n\nValue of sum = %d", sum);

//printing the address of the variable sum

printf("\nAddress of sum = %u", &sum);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no1 = it will hold the integer value of number input.
no2 = it will hold the integer value of number input.
no3 = it will hold the integer value of number input.
sum = it will hold the integer value of number input.

Display message to Take input number from the user and scan the input number.

Program code to print the data and address of the given number.

C Program to Sort a String

In this tutorial, we will learn to create a C program that will Sort a String in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in c programming.
String functions of c programming.
Conditional Statements in the C programming

Sort a String

As we all know the String is a collection of character data types. In strings, only one variable is declared which can store multiple values. First, we will give the input string to the program. Then will Sort a String by finding its length and sending it to a for loop with conditional statements in nested for loop.

With the help of this program, we can Sort a String.

Algorithm:-

1. Declare the variables for the program. 

2. Give the input string from the user. 

3. Passing that string to nested for loop.

4. Sorting with the conditional statements. 

5. Print the string. 

6. End the program.

1. Declare the variables for the program.

2. Give the input string from the user.

3. Passing that string to nested for loop.

4. Sorting with the conditional statements.

5. Print the string.

6. End the program.

Program to Sort a String:-

/*
C Program to Sort a String
*/
#include <stdio.h>
//inporting the string.h file for supportof the string functions
#include <string.h>

int main () 
{
   //declaring the variables for the program 
   char string[] = "w3addalearning";
   char temp;
   int i, j;
   //Getting the length of the string
   int no = strlen(string);

   //Printing before sorting the string
   printf("String before sorting - %s \n", string);

   for (i = 0; i < no-1; i++) {
      for (j = i+1; j < no; j++) {
         if (string[i] > string[j]) {
            temp = string[i];
            string[i] = string[j];
            string[j] = temp;
         }
      }
   }
   //Printing After sorting the string
   printf("String after sorting  - %s \n", string);
   return 0;
}

C Program to Sort a String

#include <stdio.h>

//inporting the string.h file for supportof the string functions

#include <string.h>

int main ()

{

//declaring the variables for the program

char string[] = "w3addalearning";

char temp;

int i, j;

//Getting the length of the string

int no = strlen(string);

//Printing before sorting the string

printf("String before sorting - %s \n", string);

for (i = 0; i < no-1; i++) {

for (j = i+1; j < no; j++) {

if (string[i] > string[j]) {

temp = string[i];

string[i] = string[j];

string[j] = temp;

}

//Printing After sorting the string

printf("String after sorting - %s \n", string);

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

string[] = it will hold the string value.
temp = it will hold the string value.
i = it will hold the string value.
j = it will hold the string value.

Finding the length of the string.

Printing before sorting.

Printing the output.

C Program to Print Array Elements at Even Position

In this tutorial, we will learn to create a C program that will Print Array Elements at Even Positions in C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in C programming.
Conditional Statements in C programming.
Arithmetic Operators in C programming.

Print Array Elements at Even Positions

As we all know array is a collection of similar data type elements. In an array, only one variable is declared which can store multiple values. First will take the number of elements of an array from the user. Then will take the elements from the user for the array. And at last, we will Print Array Elements at Even Positions C Programming Language.

With the help of this program, we can Print Array Elements at Even Positions.

Algorithm:-

1. Declare the variables for the program. 

2. Take making the array. 

3. Adding the elements in the array. 

4. Sending that array to the for loop. 

5. Print the elements of array of the <strong>Even </strong>index values. 

6. End the program.

1. Declare the variables for the program.

2. Take making the array.

3. Adding the elements in the array.

4. Sending that array to the for loop.

5. Print the elements of array of the <strong>Even </strong>index values.

6. End the program.

Program to Print Array Elements at Even Positions:-

/* C Program to Print Array Elements at Even Position */
#include<stdio.h>

int main()
{
    //declaring the variables for the program. 
    int arr[10], i;
    
    //adding the elements in the array by taking input from the user.
    printf("Enter any 10 array elements: ");
    
    //input for loop to take elements of array
    for(i=0; i<10; i++)
        scanf("%d", &arr[i]);
        
        //printing the output of the program
    printf("\nValues stored at even position are:\n");
    for(i=0; i<10; i++)
    {
        if(i%2==0)
        //Printing the array elements located on the Even positions 
            printf("%d ", arr[i]);
    }

    return 0;
}

/* C Program to Print Array Elements at Even Position */

#include<stdio.h>

int main()

{

//declaring the variables for the program.

int arr[10], i;

//adding the elements in the array by taking input from the user.

printf("Enter any 10 array elements: ");

//input for loop to take elements of array

for(i=0; i<10; i++)

scanf("%d", &arr[i]);

//printing the output of the program

printf("\nValues stored at even position are:\n");

for(i=0; i<10; i++)

{

if(i%2==0)

//Printing the array elements located on the Even positions

printf("%d ", arr[i]);

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

arry[10] = it will hold the string value.
i = it will hold the integer value for controlling the loop.

Getting the elements in the array for printing the Even index values.

For Loop for input.

Calculating the array elements of the Even index values.

Printing the output for the Even Index values.

C Program to Print Prime Numbers

In this tutorial, we will learn to create a C program that will Print Prime Numbers using C programming.

Prerequisites

Before starting with this tutorial we assume that you are best aware of the following C programming topics:

Operators in C Programming.
Basic Input and Output function in C Programming.
Basic C programming.
For loop in C programming.
Conditional Statements in C programming.
Arithmetic operations in C Programming.

Program to Print Prime Numbers

In c programming, it is possible to take numerical input from the user and check if that number is Prime Number or not with the help of a very small amount of code. The prime number means a number that is only divisible by itself. The C language has many types of header libraries that have supported functions in them with the help of these files the programming is easy.

With the help of this program, we can Print Prime Numbers.

Algorithm:-

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a prime number or not.

4. Printing the result.

5. End the program.

1. Declaring the variables for the program.

2. Taking the input number from the user.

3. Calculating the number is a prime number or not.

4. Printing the result.

5. End the program.

Program to Print Prime Numbers:-

#include <stdio.h>
int main() 
{
  //declaring the variables for the program 
  int no, i, flag = 0;
   //i for controlling the loop
   //no for taking the input number from the user
   //flag to store the temporary value for the program
  
  //taking input from the user for checking
  printf("Enter any positive integer: ");
  scanf("%d", &no);
  //For loop to check the number with conditions
  for (i = 2; i <= no / 2; ++i) {
    // condition for non-prime
    if (no % i == 0) {
      flag = 1;
      break;
    }
  }
  //printing the output for the given numbers.
  if (no == 1) {
    //zero is not considered as a prime number
    printf("1 is neither prime nor composite.");
  } 
  else {
    if (flag == 0)
      //if the number is a prime number then this message is shown
      printf("%d is a prime number.", no);
    else
     //else not a prime number is shown
      printf("%d is not a prime number.", no);
  }

  return 0;
}

#include <stdio.h>

int main()

{

//declaring the variables for the program

int no, i, flag = 0;

//i for controlling the loop

//no for taking the input number from the user

//flag to store the temporary value for the program

//taking input from the user for checking

printf("Enter any positive integer: ");

scanf("%d", &no);

//For loop to check the number with conditions

for (i = 2; i <= no / 2; ++i) {

// condition for non-prime

if (no % i == 0) {

flag = 1;

break;

}

//printing the output for the given numbers.

if (no == 1) {

//zero is not considered as a prime number

printf("1 is neither prime nor composite.");

}

else {

if (flag == 0)

//if the number is a prime number then this message is shown

printf("%d is a prime number.", no);

else

//else not a prime number is shown

printf("%d is not a prime number.", no);

}

return 0;

}

Output:-

In the above program, we have first initialized the required variable.

no= it will hold the integer value of the input.
i = it will hold the integer value.
flag = it will hold the integer value.

Input message for the user for the integer value.

Program Logic Code.

Printing output prime number or not.